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jarptica [38.1K]
3 years ago
8

The measure of one of the small angles of a right triangle is 14 more than 3 times the measure of the other small angle. Find th

e measure of both angles (in degrees).
Mathematics
1 answer:
anzhelika [568]3 years ago
3 0

Step-by-step explanation:

Lets assume that angle of right angle trangles are <a,<b and <c

here one of the angle is 90°

so, <a=90°

now,

By the question

<c=3×<b+14

again,

<a+<b+<c=180° (being sum of interior angles of trangles)

90°+<b+(3×<b+14)=180° ( including the value of <a and <c)

90°+<b+3<b+14=180°

4<b=180-90-14

<b=86/4

<b=19°

<c=3×<b+14

=3×19+14

<c=71

smallest angle is 19°

and another small angle is 71°

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For this case we have:
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 c = 16 cm
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 For y:
 c ^ 2 = y ^ 2 + y ^ 2
 y = c / root (2) = 16 / root (2) = 11.3137 cm
 The diagonal is:
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 d = 21.2132 + 11.3137
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 Then, the height is:
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the area of an isosceles trapezoid is:
 
A = 529 cm ^ 2
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