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3 years ago

13

Using an ideal machine a worker exerts an effort force of 8.00 N to life a 2.95 kg weight a distance of 6:00 am over what distan

ce does the worker apply his force?

1 answer:

cestrela7 [59]3 years ago

3 0

Answer:

29.5 ×6= 8×d

d = 29.5×6/8 = 22.12 m

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10. Use the discriminant to find the values of b for which the equation 4x2 + bx + 1 = 0 has one real solution.

il63 [147K]

Answer:

b = 4, or -4

Step-by-step explanation:

b^2 - 4*4*1 = 0

b^2 = 16

b = 4, or -4

8 0

2 years ago

4x+y=8 and x+3y=8 graphed

IRISSAK [1]

$standard \ linear \ equation\ :\\\\y=ax+b\\\\ \begin{cases} 4x+y=8\ \ |\ subtract\ 4x\ to\ both\ sides\\ x+3y=8 \ \ |\ subtract\ x\ to\ both\ sides \end{cases}\\\\\begin{cases} y=-4x+8 \\ 3y=-x+8\ \ | \ divide \ each \ term \ by \ 3 \end{cases}$

$\begin{cases} y=-4x+8 \\ y=-\frac{1}{3}x+\frac{8}{3} \end{cases}\\\\y=-4x+8\\ To \ find \ the \ x-axis \ intersection \ point, \\set \ y \ equal \ to \ zero \ and \ solve \ for \ x : \\ \\y=0 \ \to 0=-4x+8\\\\4x=8 \ \ | \ divide \ both \ sides\ by\ 4 \\\\x=2\\\\ point : \ \ (2,0)$

$To \ find \ the \ y-axis \ intersection \ point, \\set \ x \ equal \ to \ zero \ and \ solve \ for \ y : \\ \\x=0 \ \to y=-4 \cdot 0+8\\ y=8 \\ point: \ \ (0,8)$

$y=-\frac{1}{3}x+\frac{8}{3}\\\\ \ the \ x-axis \ intersection \ point \\ \\y=0 \ \to 0=-\frac{1}{3}x+\frac{8}{3}\\ \frac{1}{3}x=\frac{8}{3} \ \ | \ multiply\ both\ sides\ by\ 3 \\\\x=8 \\\\point: \ \ (8,0)$

$the \ y-axis \ intersection \ point \\ \\x=0 \ \to y=-\frac{1}{3} \cdot 0+\frac{8}{3} \\ y=\frac{8}{3} \\ point : \ \ (0,\frac{8}{3})$

$Answer :\\\\ \begin{cases} y=-4x+8 \ \ | \ multiply \ each \ term \ by \ (-3) \\ 3y=-x+8 \end{cases}\\\begin{cases} -3y=12x-24 \\ 3y=-x+8 \end{cases}\\+-------\\0=11x-16\\11x=16\ \ | \ divide \ both \ sides\ by\ 11\\x=\frac{16}{11}$

$y=-4 \cdot \frac{16}{11}+8 \\ y=- \frac{ 64}{11}+\frac{88}{11}\\y= \frac{24}{11}\\\\\begin{cases} x=\frac{16}{11} \\ y=\frac{24}{11} \end{cases}$

3 0

3 years ago

How do you solve this equation? 8=3(q-10)-10

IRISSAK [1]

Q = 16
View the attached image for work!

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3 years ago

The edge length of a cube is 17 cm. Identify the length of its diagonal. Round to the nearest tenth, if necessary. HELP PLEASE!!

lara31 [8.8K]

Answer:

29.4 cm

Step-by-step explanation:

The length of the space diagonal can be found to be the root of the squares of the three orthogonal edge lengths. For a cube, those edge lengths are all the same, so the diagonal length is ...

d = √(17^2 + 17^2 +17^2) = 17√3 ≈ 29.4 . . . . cm

_____

Consider a rectangular prism with edge lengths a, b, c. Then the face diagonal of the face perpendicular to edge "a" has length ...

(face diagonal)^2 = (b^2 +c^2)

and the space diagonal has length ...

(space diagonal)^2 = a^2 + (face diagonal)^2 = a^2 +b^2 +c^2

So, the length of the space diagonal is ...

space diagonal = √(a^2 +b^2 +c^2)

when the prism is a cube, these are all the same (a=b=c). This is the formula we used above.

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3 years ago

Use an inequality to describe the interval of real numbers <br><br>(-3,8]

Naya [18.7K]

38 i think it means infinite

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3 years ago