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Shtirlitz [24]
3 years ago
13

Using an ideal machine a worker exerts an effort force of 8.00 N to life a 2.95 kg weight a distance of 6:00 am over what distan

ce does the worker apply his force?
Mathematics
1 answer:
cestrela7 [59]3 years ago
3 0

Answer:

29.5 ×6= 8×d

d = 29.5×6/8 = 22.12 m

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A group of learners is trying to identify the vertices of the feasible region from the graph shown below during a Live Classroom
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2 years ago
(-0.75+6)-1(2.5x+-1.9
fenix001 [56]

Simplifying

(0.75x + 6) + -1(2.5x + -1.9) = 0


Reorder the terms:

(6 + 0.75x) + -1(2.5x + -1.9) = 0


Remove parenthesis around (6 + 0.75x)

6 + 0.75x + -1(2.5x + -1.9) = 0


Reorder the terms:

6 + 0.75x + -1(-1.9 + 2.5x) = 0

6 + 0.75x + (-1.9 * -1 + 2.5x * -1) = 0

6 + 0.75x + (1.9 + -2.5x) = 0


Reorder the terms:

6 + 1.9 + 0.75x + -2.5x = 0


Combine like terms: 6 + 1.9 = 7.9

7.9 + 0.75x + -2.5x = 0


Combine like terms: 0.75x + -2.5x = -1.75x

7.9 + -1.75x = 0


Solving

7.9 + -1.75x = 0


Solving for variable 'x'.


Move all terms containing x to the left, all other terms to the right.


Add '-7.9' to each side of the equation.

7.9 + -7.9 + -1.75x = 0 + -7.9


Combine like terms: 7.9 + -7.9 = 0.0

0.0 + -1.75x = 0 + -7.9

-1.75x = 0 + -7.9


Combine like terms: 0 + -7.9 = -7.9

-1.75x = -7.9


Divide each side by '-1.75'.

x = 4.514285714


Simplifying

x = 4.514285714

5 0
3 years ago
Read 2 more answers
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