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Vikentia [17]
2 years ago
5

A piece of rope 27m long is cut into two pieces so that one piece is four-fifths as long as the other. Find the length of each p

iece
Mathematics
1 answer:
nata0808 [166]2 years ago
8 0

Answer:

x+.8x=27

1.8x=27

x=15

4/5(15)=12

So 15 and 12

Step-by-step explanation:

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Find the greatest common factor of the following monomial.<br> 37x^3y^6 x^6y^2
nordsb [41]
<span>37x^3y^6 and x^6y^2
</span>greatest common factor: x^3y^2
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3 years ago
Ques no 1 b) help me!!!!! <br> I will give you brainliest plzzz
saul85 [17]

Answer:

-4/5

Step-by-step explanation:

r=x/2

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2 years ago
More on fraction <br><br>21×5​
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Answer:

105.

Step-by-step explanation:

21+21+21+21+21=105.

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3 years ago
Given f(x)=x^2-2x find f(6)
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Step-by-step explanation:

In the picture, I hope that it's a clear solution.

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Read 2 more answers
The prices of all college textbooks follow a bell-shaped distribution with a mean of $113 and a standard deviation of $12. Using
Soloha48 [4]

Step-by-step explanation:

In statistics, the empirical rule states that for a normally distributed random variable,

  • 68.27% of the data lies within one standard deviation of the mean.

  • 95.45% of the data lies within two standard deviations of the mean.

  • 99.73% of the data lies within three standard deviations of the mean.

In mathematical notation, as shown in the figure below (for a standard normal distribution), the empirical rule is described as

                             \Phi(\mu \ - \ \sigma \ \leq X \ \leq \mu \ + \ \sigma) \ = \ 0.6827 \qquad (4 \ \text{s.f.}) \\ \\ \\ \Phi(\mu \ - \ 2\sigma \ \leq X \ \leq \mu \ + \ 2\sigma) \ = \ 0.9545 \qquad (4 \ \text{s.f.}) \\ \\ \\ \Phi}(\mu \ - \ 3\sigma \ \leq X \ \leq \mu \ + \ 3\sigma) \ = \ 0.9973 \qquad (4 \ \text{s.f.})

where the symbol \Phi (the uppercase greek alphabet phi) is the cumulative density function of the normal distribution, \mu is the mean and \sigma is the standard deviation of the normal distribution defined as N(\mu, \ \sigma).

According to the empirical rule stated above, the interval that contains the prices of 99.7% of college textbooks for a normal distribution N(113, \ 12),

                \Phi(113 \ - \ 3 \ \times \ 12 \ \leq \ X \ \leq \ 113 \ + \ 3 \ \times \ 12) \ = \ 0.9973 \\ \\ \\ \-\hspace{1.75cm} \Phi(113 \ - \ 36 \ \leq \ X \ \leq \ 113 \ + \ 36) \ = \ 0.9973 \\ \\ \\ \-\hspace{3.95cm} \Phi(77 \ \leq \ X \ \leq \ 149) \ = \ 0.9973

Therefore, the price of 99.7% of college textbooks falls inclusively between $77 and $149.

5 0
2 years ago
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