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3 years ago

What is the square root of 53 rounded to the nearest hundreth

Mathematics

2 answers:

Temka [501]3 years ago

8 0

7.28
hope i helped ya pal :3

allsm [11]3 years ago

4 0

7.28 is the answer rounded to the nearest hundredth.
7.28010988928

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PLEASE SOLVE AND CHECK. SHOW COMPLETE SOLUTION

Alex17521 [72]

Solution:

$\sqrt{4x + 13} = x + 2$

First square both sides.

$= > ( \sqrt{4x + 13} ) ^{2} = (x + 2) ^{2}$

Now, square root and square gets cancel out in the LHS. And in the RHS, apply the identity: (a + b)² = a² + 2ab + b².

$= > 4x + 13 = {(x)}^{2} + 2 \times x \times 2 + (2) ^{2} \\ = > 4x + 13 = {x}^{2} + 4x + 4$

Now, transpose 4x and 4 to LHS.

$= > 4x - 4x + 13 - 4 = {x}^{2} \\$

Now, do the addition and subtraction.

$= > {x}^{2} = 9 \\ = > x = \sqrt{9} \\ = > x = ±3$

Answer:

x = ± 3

Hope you could understand.

If you have any query, feel free to ask.

3 0

2 years ago

An electrical power company is looking to expand into a new market. Before they commit to supplying the new area with electricit

TiliK225 [7]

Answer:

atleast 385

Step-by-step explanation:

Given that an electrical power company is looking to expand into a new market. Before they commit to supplying the new area with electricity, they would like know the mean daily power usage for homes there.

Population std deviation = $\sigma = 50$

Sample size = $n$

STd error of sample mean = $\frac{50}{\sqrt{n} }$

Margin of error for 95% would be Critical value ( std error)

Here since population std dev is known we can use Z critical value= 1.96

$1.96*\frac{50}{\sqrt{n} }19.6^2\\n>384.16$

Sample size should be atleast 385

5 0

3 years ago

What is an equation that passes through the point (-2,-3) and is parallel to the line 5x+2y=14

Alekssandra [29.7K]

Answer:

$5x-2y=16$

Hope this helps! If you need an explanation, I've got you.

6 0

3 years ago

Simplify 4 to the seventh power over 5 squared all raised to the third power . (4 points)

julsineya [31]

Answer: The answer is C, 4 to the 21st over 5 to the 6th power.

4 0

2 years ago

Please help expand the expression using pascal's triangle (1-2x)^4

aliya0001 [1]

(1 - 2x)⁴
(1 - 2x)(1 - 2x)(1 - 2x)(1 - 2x)
[1(1 - 2x) - 2x(1 - 2x)][1(1 - 2x) - 2x(1 - 2x)]
[1(1) - 1(2x) - 2x(1) - 2x(-2x)][1(1) - 1(2x) - 2x(1) - 2x(-2x)]
(1 - 2x - 2x + 4x²)(1 - 2x - 2x + 4x²)
(1 - 4x + 4x²)(1 - 4x + 4x²)
1(1 - 4x + 4x²) - 4x(1 - 4x + 4x²) + 4x²(1 - 4x + 4x²)
1(1) - 1(4x) + 1(4x²) - 4x(1) - 4x(-4x) - 4x(4x²) + 4x²(1) - 4x²(4x) + 4x²(4x²)
1 - 4x + 4x² - 4x + 16x² - 16x³ + 4x² - 16x³ + 16x⁴
1 - 4x - 4x + 4x² + 16x² + 4x² - 16x³ - 16x³ + 16x⁴
1 - 8x + 24x² - 32x³ + 16x⁴

5 0

3 years ago

Read 2 more answers