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1 answer:
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This problem can be modeled by the picture shown below. We notice that we are given to side lengths, specifically legs, of the triangle. Therefore, we can use the Pythagorean Theorem, which states that a^2+b^2=c^2, where a and b are legs and c is the hypotenuse. So we can do:
16^2+12^2=c^2
256+144=c^2
400=c^2
The square root of 400 is 20, which is our hypotenuse.
(You might wonder why we used 12, that is because the whole base length is 24, but we only need half of the base to use the Pythagorean Theorem. 24/2 is 12).
:)
16^2+12^2=c^2
256+144=c^2
400=c^2
The square root of 400 is 20, which is our hypotenuse.
(You might wonder why we used 12, that is because the whole base length is 24, but we only need half of the base to use the Pythagorean Theorem. 24/2 is 12).
:)
Answer:
A), B) and D) are true
Step-by-step explanation:
A) We can prove it as follows:
B) When you compute the product Ax, the i-th component is the matrix of the i-th column of A with x, denote this by Ai x. Then, we have that . Now, the colums of A are orthonormal so we have that (Ai x)^2=x_i^2. Then
.
C) Consider . This set is orthogonal because
, but S is not orthonormal because the norm of (0,2) is 2≠1.
D) Let A be an orthogonal matrix in . Then the columns of A form an orthonormal set. We have that
. To see this, note than the component
of the product
is the dot product of the i-th row of
and the jth row of
. But the i-th row of
is equal to the i-th column of
. If i≠j, this product is equal to 0 (orthogonality) and if i=j this product is equal to 1 (the columns are unit vectors), then
E) Consider S={e_1,0}. S is orthogonal but is not linearly independent, because 0∈S.
In fact, every orthogonal set in R^n without zero vectors is linearly independent. Take a orthogonal set and suppose that there are coefficients a_i such that
. For any i, take the dot product with u_i in both sides of the equation. All product are zero except u_i·u_i=||u_i||. Then
then
.
The radius of a sphere that has a surface area of 12.56in2 would turn out to be:
4
r²
4