Answer:
There are 585 adults and children
Step-by-step explanation:
Let the number of adults be a, number of children be c and the number of seniors be a
Amount made per group;
adults; 52 * a = 52a
Children : 26 * c = 26c
Seniors = 20 * s = 20s
Adding all will give 20,490
52a + 20s + 26c = 20 490 ••••(i)
Now let us work with the ratios;
a : s = 6 : 1
a/s = 6/1
a = 6s •••••(ii)
Lastly;
a/c = 4/9
4c = 9a ••••(ii)
We want to get a + c
From the first equation , let’s substitute
52(6s) + 20s + 26c = 20,490
26c = 6.5 (4c)
but 4c = 9a; 6.5(9a)
But a = 6s
So we have; 6.5(9)(6s) = 351s
so we have;
312s + 351s + 20s = 20,490
683s = 20,490
s = 20490/683
s = 30
Recall;
a = 6s = 6 * 30 = 180
4c = 9a
4c = 9 * 180
c = (9 * 180)/4 = 405
So the total number of children and adult is a + c
405 + 180 = 585
<h3>x²+5x+3+2x²+10x15 =0</h3><h3>x²+2x²+5x+10x+3+15=0</h3><h3>3x²+15x+18=0</h3><h3>3(x²+5x+6) =0 because 3 is common factor</h3><h3>3(x²+3x+2x+6) spill the middle term</h3><h3>3(x(x+3)+2(x+3) take the common factor from term</h3><h3>3(x+2) (x+3)</h3>
<h3>answer is 3(x+2) (x+3)</h3>
please mark this answer as brainlist
Answer:
The best estimate for the money in Karita's account now is $151.
Step-by-step explanation:
Given:
Karita had $138.72 in her checking account.
She wrote checks for $45.23 and $18.00.
Then she made a deposit of $75.85 into her account.
Now, to find the best estimate for the money in Karita's account now.
<em>Initial account = $138.72.</em>
<em>Deducted amount = $45.23+$18.00=$63.23.</em>
So, the amount after deduction:
$138.72 - $63.23 = $75.49.
Now, the amount after deposit:
$75.49 + $75.85 = $151.34.
Therefore, the best estimate for the money in Karita's account now is $151.
Let his normal weight = 100%
He is 10% more so he is 110%
Divide his weight now by 110% to find his normal weight.
88/1.1 = 80
His normal weight is 80 kg
We can determine that there are two types of soup: one can costing $0.54, and the other costing $0.34. 5 cans of the $0.54 soup would cost a total of $2.70, while 5 cans of the $0.34 soup would cost $1.70. Therefore, the combined cost of all 10 cans of soup, being 5 of each type, is $4.40.
