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dalvyx [7]
3 years ago
7

The probability that a new advertising campaign will increase sales is assessed as being 0.80. The probability that the cost of

developing the new ad campaign can be kept within the original budget allocation is 0.40. Assuming that the two events are independent, the probability that the cost is kept within budget or the campaign will increase sales is:
Mathematics
1 answer:
tatuchka [14]3 years ago
5 0

Answer:

The probability that the cost is kept within budget or the campaign will increase sales is 0.88

Step-by-step explanation:

The probability that the cost is kept within budget (event A) <u>or</u> the campaign will increase sales (event B) is the <u>union</u> of the probability of those two events. By basic properties of probability, this is:

P(A ∪ B) = P(A) + P (B) - P(A ∩ B)

and for independent events:

P(A ∩ B) = P(A) * P(B)

So:

P(A ∪ B) = 0.80 + 0.40 - (0.80*0.40) = 1.20 - 0.32 = 0.88

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given the weekly demand curve of a local wine producer is p= 50-0.1q, and that the total cost function is c= 1500+ 10q, where q
ipn [44]

Answer:

a)the weekly profit as a function of price isP=-10 p^2 + 600 p - 6500

b) a bottle of wine be sold at $30 to realise maximum profit

c) the maximum profit that can be made by the producer is $2500

Step-by-step explanation:

The weekly demand curve of a local wine producer is p= 50-0.1q

p = price

q = quantity

Revenue function R =Price \times Quantity

R=(50-0.1q)q

R=50q-0.1q^2

Cost function: c= 1500+ 10q

Profit function=R(x)-C(x)

Profit function= 50q-0.1q^2-1500-10q

Profit function= 40q-0.1q^2-1500   ----1

We have q = 500 - 10 p using p = 50 − 0.1q

P=-0.1 (500 - 10 p)^2 + 40 (500 - 10 p)- 1500\\P= -10 p^2 + 600 p - 6500

General quadratic equation:ax^2+bx+c=0

On comparing

a = -0.1 , b = 40 , c = -1500

Maximum Profit is at q = \frac{-b}{2a}=\frac{-40}{2(-0.1)}=200

To find price must a bottle of wine be sold to realise maximum profit

p= 50-0.1q

p= 50-0.1(200)=30

Substitute the value of q in profit function(1) get the maximum profit

So, Profit function= 40\left(200\right)-0.1\left(200\right)^{2}-1500=2500

Hence

a)the weekly profit as a function of price isP=-10 p^2 + 600 p - 6500

b) a bottle of wine be sold at $30 to realise maximum profit

c) the maximum profit that can be made by the producer is $2500

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Step-by-step explanation:

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Answer:

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For this type of problem,

It is stated that the weight of steel is 32.6 lbs per foot

Meaning, every foot of steel beam weighs 32.6.

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