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3 years ago

If f(x) = –3x – 2, what is f(–5)?

Mathematics

1 answer:

Step2247 [10]3 years ago

3 0

F(x) = -3x - 2
f(-5) = -3(-5) -2 = 15 - 2 = 13

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alabama power came by my house that i just bought and installed a new wire support for one of the telephone poles on the propert

PolarNik [594]

Answer:

30 feets

Step-by-step explanation:

subtrqct 55-25 = 30

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3 years ago

In the expansion of (3a + 4b)8, which of the following are possible variable terms? Explain your reasoning. a2b3; a5b3; ab8; b8;

Fiesta28 [93]

We have to find the expansion of $(3a+4b)^{8}$

We will use binomial expansion to expand the given expression, which states that the expression $(a+b)^{n}$ is expanded as :

$(a+b)^{n}=^{n}C_{0}a^{n}+^{n}C_{1}a^{n-1}b+^{n}C_{2}a^{n-2}b^{2}+........^{n}C_{n}b^{n}$

Now expanding $(3a+4b)^{8}$ we get,

$(3a+4b)^{8}=^{8}C_{0}(3a)^{8}+^{8}C_{1}(3a)^{7}(4b)+^{8}C_{2}(3a)^{6}(4b)^{2}+^{8}C_{3}(3a)^{5}(4b)^{3}+^{8}C_{4}(3a)^{4}(4b)^{4}+^{8}C_{5}(3a)^{3}(4b)^{5}+^{8}C_{6}(3a)^{2}(4b)^{6}+^{8}C_{7}(3a)(4b)^{7}+^{8}C_{8}(4b)^{8}$

$(3a+4b)^{8}=^{8}C_{0}(3)^{8}a^{8}+^{8}C_{1}(3)^{7}(4)(a^{7}b)+^{8}C_{2}(3)^{6}(4)^{2}(a^{6}b^{2})+^{8}C_{3}(3)^{5}(4)^{3}(a^{5}b^{3})+^{8}C_{4}(3)^{4}(4)^{4}(a^{4}b^{4})+^{8}C_{5}(3)^{3}(4)^{5}(a^{3}b^{5})+^{8}C_{6}(3)^{2}(4)^{6}(a^{2}b^{6})+^{8}C_{7}(3)(4)^{7}(ab^{7})+^{8}C_{8}(4)^{8}(b^{8})$

So, the variables are $a^{5}b^{3}$ , $b^{8}$ , $a^{4}b^{4}$ , $a^{8} , [tex] ab^{7}$

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3 years ago

A $120 wagon is on sale for 15 percent off. What is the sale price of the wagon?

melamori03 [73]

Answer:

Step-by-step explanation:

120*15%= 18 off

120-18= $102.00 new price

7 0

3 years ago

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Two ropes, AD and BD, are tied to a peg on the ground at point D. The other ends of the ropes are tied to points A and B on a fl

Lisa [10]

Answer: 5(√3-1) unit.

Step-by-step explanation:

Since, By the below diagram,

For triangle BDC,

We can write,

$tan 30^{\circ}=\frac{BC}{DC}$

⇒ $\frac{1}{\sqrt{3}}=\frac{BC}{5\sqrt{3}}}$

⇒ $\sqrt{3}=\frac{5\sqrt{3}}{BC}$

⇒ $BC=\frac{5\sqrt{3} }{\sqrt{3} }$

⇒ $BC=5\text{ unit}$

Now, In triangle ADC,

$tan45^{\circ}=\frac{AC}{DC}$

⇒ $1=\frac{AB+BC}{DC}$

⇒ $1=\frac{DC}{AB+BC}$

⇒ $1=\frac{5\sqrt{3}}{AB+5}$

⇒ $AB+5=5\sqrt{3}$

⇒ $AB=5\sqrt{3}-5=5(\sqrt{3}-1)\text{ unit}$

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3 years ago

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Mike earns $6.50 per hour plus 4% of his sales enter an equation for mikes total earnings, e, when he works x hours and has a to

Cerrena [4.2K]

First identify what each variable means. since X is the amount of hours he works, and he makes $6.50 an hour, you know you need to multiply those two numbers together creating the 6.50x. You also know Y is his total sales, and he earns 4% of Y. To find 4% of Y you need to turn the percent into a decimal, and to do this you move the decimal two spaces to the left. Since 4 is a whole number, the decimal is after the 4 so you get .04 as your decimal. Then youd multiply .04 by Y getting .04y. Lastly you add 6.50x + .04y to get E, mikes total earnings. So your final equation is

6.50x + .04y = e

Hope this all makes sense

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3 years ago

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