Answer:
Step-by-step explanation:
The change of distance over time of the plain A is 300 mi/hour and 200 mi/hour for plane B. O is the point of the airport.
So, the distance from A to O AO = 90 miles and BO = 120 miles.
Now, we have a right triangle here. We can use the Pythagorean theorem, so the distance between the planes will be:
(1)
If we take the derivative of the equation (1) we could find the change of the distance between planes.
Finally,
I hope it helps you!
Answer:
$168
Step-by-step explanation:
1 dozen = 12
proportions
12 books ⇔ $144
14 books ⇔ $B
B = 144*14/12
B = $168
X + y = 20---- 1
x - y = 8----- 2
From 1+2
2x = 28
x = 14
Substitute x in eq.2
14 -y = 8
y = 6
Ans : x= 14 , y= 6
<em>θ</em> is given to be in the fourth quadrant (270° < <em>θ</em> < 360°) for which sin(<em>θ</em>) < 0 and cos(<em>θ</em>) > 0. This means
cos²(<em>θ</em>) + sin²(<em>θ</em>) = 1 ==> sin(<em>θ</em>) = -√[1 - cos²(<em>θ</em>)] = -3/5
Now recall the double angle identity for sine:
sin(2<em>θ</em>) = 2 sin(<em>θ</em>) cos(<em>θ</em>)
==> sin(2<em>θ</em>) = 2 (-3/5) (4/5) = -24/25
When you evaluate the equation you plug in the numbers or replace the variables with the numbers it’s giving you.
-8(2)(-32) - 2(-8) + 4
-16(-32) - 16 + 4
512 + 20
= 532
Hope this helps!
