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2 years ago

In the evolution of the internet which event occurred most recently ?

Computers and Technology

1 answer:

IceJOKER [234]2 years ago

7 0

anime websites were banned on the internet which made internet evolution take a huge step back

Explanation:

without anime why are you even here?

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How many comparisons will be done to find 8 in this list using a linear search?

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Answer:

I think 4 comparisons

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3 years ago

New evidence can lead to a change in scientific knowledge.<br><br> A. True<br> B.False

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3 years ago

Read 2 more answers

There are two algorithms called Alg1 and Alg2 for a problem of size n. Alg1 runs in n2 microseconds and Alg2 runs in 100n log n

nataly862011 [7]

The answer & explanation for this question is given in the attachment below.

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3 years ago

Write a program that helps a young student learn to make change. Use the random number generator to generate change amounts betw

erastovalidia [21]

Answer:

#include <iostream>

#include <stdlib.h>

using namespace std;

int main()

{

srand(time(0));

int coins = rand()%99 + 1;

int temp = coins;

cout<<"Enter the coins needed to make $0."<<coins<<"?"<<endl<<endl;

int a, b, c, d;

cout<<"Quarters? ";

cin>>a;

cout<<"Dimes? ";

cin>>b;

cout<<"Nickles? ";

cin>>c;

cout<<"Pennies? ";

cin>>d;

int quarters = coins/25;

coins = coins%25;

int dimes = coins/10;

coins = coins%10;

int nickles = coins/5;

coins = coins%5;

int pennies = coins/1;

if(((a*25) + (b*10) + (c*5) + (d*1))==temp)

{

cout<<"That's correct"<<endl;

if(a!=quarters || b!=dimes || c!=nickles || d!=pennies)

{

cout<<"The optimized solution is "<<endl;

}

else

{

cout<<"Not correct"<<endl;

cout<<"The solution is "<<endl;

}

cout<<"\tQuarters: "<<quarters<<endl;

cout<<"\tDimes: "<<dimes<<endl;

cout<<"\tNickles: "<<nickles<<endl;

cout<<"\tPennies: "<<pennies<<endl;

return 0;

}#include <iostream>

#include <stdlib.h>

using namespace std;

int main()

{

srand(time(0));

int coins = rand()%99 + 1;

int temp = coins;

cout<<"Enter the coins needed to make $0."<<coins<<"?"<<endl<<endl;

int a, b, c, d;

cout<<"Quarters? ";

cin>>a;

cout<<"Dimes? ";

cin>>b;

cout<<"Nickles? ";

cin>>c;

cout<<"Pennies? ";

cin>>d;

int quarters = coins/25;

coins = coins%25;

int dimes = coins/10;

coins = coins%10;

int nickles = coins/5;

coins = coins%5;

int pennies = coins/1;

if(((a*25) + (b*10) + (c*5) + (d*1))==temp)

{

cout<<"That's correct"<<endl;

if(a!=quarters || b!=dimes || c!=nickles || d!=pennies)

{

cout<<"The optimized solution is "<<endl;

}

else

{

cout<<"Not correct"<<endl;

cout<<"The solution is "<<endl;

}

cout<<"\tQuarters: "<<quarters<<endl;

cout<<"\tDimes: "<<dimes<<endl;

cout<<"\tNickles: "<<nickles<<endl;

cout<<"\tPennies: "<<pennies<<endl;

return 0;

}

Explanation:

Use the built-in rand function to generate a random coin.
Get all the required values for quarters, dimes, nickles and pennies and store them in variables.
Check if the coins give a value of temp, then answer is correct and the values of user will be added.
Optimum solution is displayed If it does not matches with the optimum solution. Display that the answer is wrong along with solution.

6 0

2 years ago

For this portion of the lab you will design the solution so that you perform some conditional tests. For this lab: 1. You will v

PIT_PIT [208]

Answer:

#Prompt the user to enter the miles.

Miles = float(input('Enter the miles to convert into kilometer: '))

#Check the miles.

if Miles >= 0 :

#Convert the miles to kilometers.

Miles_To_km = Miles*1.6

#Display the result.

print (Miles, "miles equivalent to", Miles_To_km, "kilometer.")

#Prompt the user to enter the gallons.

Gallon = float(input('Enter the gallons to convert into liter: '))

#Check the validity of the Gallons entered.

if Gallon >= 0:

#Convert gallons into liters.

Gal_To_Lit = Gallon*3.9

#Display the result.

print (Gallon, "gallons equivalent to", Gal_To_Lit, "liters.")

#Prompt the user to enter the pounds.

Pound = float(input('Enter the pounds to convert into kilograms: '))

#Check the validity of the Pounds entered.

if Pound >= 0:

#Convert pounds into kilograms.

Pounds_To_Kg = Pound*0.45

#Display the result.

print (Pound, "pounds equivalent to", Pounds_To_Kg, "kilograms.")

#Prompt the user to enter the temperature in Fahrenheit.

f = float(input('Enter the temperature in Fahrenheit: '))

#Check the value to be not greater than 1000.

if f < 1000:

#Convert Fahrenheit into celsius.

F_To_C = (f -32)*5/9

#Display the result.

print (f, "Fahrenheit equivalent to", F_To_C, "celsius.")

#Otherwise.

else:

#Display the error message.

print ("Invalid temperature (greater than 1000) !!!")

else:

#Display the error message.

print ("Pounds cannot be negative !!!")

else:

#Display the error message.

print ("Gallons cannot be negative !!!")

else:

#Display the error message.

print ("Miles cannot be negative !!!")

Explanation:

4 0

3 years ago