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Oliga [24]
3 years ago
15

All websites with medical information should be considered credible.

Computers and Technology
2 answers:
marissa [1.9K]3 years ago
7 0

not true just took the quiz



larisa [96]3 years ago
3 0
No, this is not true. WebMD is a great example asking you of simple symptoms that you may be facing and your results could present an apparent fatal disease. This constantly scares the population of netizens whenever they would want a quick diagnosis online through these medical information sites. The best solution to your symptoms is to visit your family doctor or a licensed physician who will give you proper diagnosis checking your vital signs and other related information. Do not always trust the internet and the information it gives you as a user you must take the information with discretion before reacting inappropriately. 
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Write a program that prints the U.S. presidential election years from 1792 to present day, knowing that such elections occur eve
miv72 [106K]

Answer:

The cpp program to print US presidential years is given.

#include <iostream>

using namespace std;

int main()

{

   // variable to hold presidential election year declared  

   int elec_year;

// variable to hold presidential election year initialized to 1792  

elec_year=1792;

   

// the value displayed on the console output

   std::cout << "The U.S. presidential election years from 1792 to present day are listed. " << std::endl;

   

   // loop executes till year is less than or equals 2020

   do

   {

       // initial value is printed

       std::cout << elec_year << std::endl;

       

       // value is incremented by 4

       elec_year = elec_year + 4;

       

   }while(elec_year<=2020);

   return 0;

}

OUTPUT

The U.S. presidential election years from 1792 to present day are listed.  

1792

1796

1800

1804

1808

1812

1816

1820

1824

1828

1832

1836

1840

1844

1848

1852

1856

1860

1864

1868

1872

1876

1880

1884

1888

1892

1896

1900

1904

1908

1912

1916

1920

1924

1928

1932

1936

1940

1944

1948

1952

1956

1960

1964

1968

1972

1976

1980

1984

1988

1992

1996

2000

2004

2008

2012

2016

2020

Explanation:

The program works as described.

1. An integer variable, elec_year, is declared and initialized with the first US presidential year value, 1792.

2. Inside the do-while loop, the variable, elec_year, is first printed to the console followed by a new line inserted using, endl.

3. The variable, elec_year, is then incremented by 4.

4. The do-while loop continues till the value of the variable, elec_year, does not exceeds the current year, 2020.

5. The program ends with a return statement since main() has return type int.

6. Only one variable is used in the program.

7. The program consists of only main() method since cpp is not completely object oriented programming language.

8. The same program, if written in object oriented programming language like java or c# will be written inside a class and executed through main() method.

4 0
3 years ago
What is the largest possible value that the variable x can have after the code segment executes? 17 17 A 14 14 B 11 11 C 4
Bogdan [553]

Answer:

i dont know sorry man no problem listed

Explanation:

6 0
3 years ago
What is the name of the function below?<br><br> function go(){<br> alert("hello everybody");<br> }
labwork [276]

Answer:

It’s Java script I think and it makes something say hello everybody

Explanation:

6 0
3 years ago
Which one is not an operating system?1.mac 2.Microsoft office3.Iso.3.Android
quester [9]
It's either microsoft or office. Based on research I would say office.

I really hope this helps you! :-)
6 0
3 years ago
A signal travels from point A to point B. At point A, the signal power is 100 W. At point B, the power is 90 W. What is the atte
11Alexandr11 [23.1K]

Answer:

Attenuation = 0.458\ db

Explanation:

Given

Power at point A = 100W

Power at point B = 90W

Required

Determine the attenuation in decibels

Attenuation is calculated using the following formula

Attenuation = 10Log_{10}\frac{P_s}{P_d}

Where P_s = Power\ Input and P_d  = Power\ output

P_s = 100W

P_d = 90W

Substitute these values in the given formula

Attenuation = 10Log_{10}\frac{P_s}{P_d}

Attenuation = 10Log_{10}\frac{100}{90}

Attenuation = 10 * 0.04575749056

Attenuation = 0.4575749056

Attenuation = 0.458\ db <em>(Approximated)</em>

7 0
3 years ago
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