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777dan777 [17]
3 years ago
5

The terminal side of an angle in standard position passes through P(-3,-4). What is the value of tan e?

Mathematics
1 answer:
exis [7]3 years ago
8 0

Answer:

Tan \theta= \dfrac{4}{3}

Step-by-step explanation:

Given:

The terminal side of an angle in standard position passes through P(-3,-4).

  • Point P is in Quadrant III
  • In Quadrant |||, Tan \theta is positive.

Tan \theta= \dfrac{Opposite}{Adjacent}\\Tan \theta= \dfrac{y}{x}\\Tan \theta= \dfrac{-4}{-3}\\Tan \theta= \dfrac{4}{3}

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When you multiply two numbers which have the same sign the answer is positive. Therefore multiply eight and three to get 24 and the answer is positive; therefor the answers 24.
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3 years ago
Please help me find the perimeter.​
slavikrds [6]

Answer:

31.42 cm (rounded up to two decimal places)

Step-by-step explanation:

We first find the circumference of the semi-circle segment:

The circumference will be given by; \frac{1}{2} × π × D (where D is the diameter)

The diameter is 6 cm so circumference is;

\frac{1}{2} × π × 6 cm = 9.42 cm (rounded up to two decimal places)

The perimeter of the figure therefore is;

8cm + 6 cm + 8 cm + 9.42 cm = 31.42 cm

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3 years ago
The real number square root of 16 belongs to which sets of numbers?
klasskru [66]

Answer: Square root of 16 is +4 or -4. Since -4 is not a natural number, the square root can be described as an integer.

Step-by-step explanation:

The square root of 16 is a rational number. The square root of 16 is 4, an integer

3 0
3 years ago
The area of a square is 9 centimeters squared (cm^2) If the sides of the square are doubled in length, what is the new area, in
Mice21 [21]

Answer:

The question says area of a square = 9 cm squared.

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7 0
3 years ago
Read 2 more answers
How many solutions does the equation sin(5x) = 1/2 have on the interval (0, 2PI]
Darina [25.2K]

Answer:

Step-by-step explanation:

Given the equation

Sin(5x) = ½

5x = arcSin(½)

5x = 30°

Then,

The general formula for sin is

5θ = n180 + (-1)ⁿθ

Divide through by 5

θ = n•36 + (-1)ⁿ30/5

θ = 36n + (-1)ⁿ6

The range of the solution is

0<θ<2π I.e 0<θ<360

First solution

When n = 0

θ = 36n + (-1)ⁿθ

θ = 0×36 + (-1)^0×6

θ = 6°

When n = 1

θ = 36n + (-1)ⁿ6

θ = 36-6

θ = 30°

When n = 2

θ = 36n + (-1)ⁿ6

θ = 36×2 + 6

θ = 78°

When n =3

θ = 36n + (-1)ⁿ6

θ = 36×3 - 6

θ = 102°

When n=4

θ = 36n + (-1)ⁿ6

θ = 36×4 + 6

θ = 150

When n =5

θ = 36n + (-1)ⁿ6

θ = 36×5 - 6

θ = 174°

When n = 6

θ = 36n+ (-1)ⁿ6

θ = 36×6 + 6

θ = 222°

When n = 7

θ = 36n + (-1)ⁿ6

θ = 36×7 - 6

θ = 246°

When n =8

θ = 36n + (-1)ⁿ6

θ = 36×8 + 6

θ = 294°

When n =9

θ = 36n + (-1)ⁿ6

θ = 36×9 - 6

θ = 318°

When n =10

θ = 36n + (-1)ⁿ6

θ = 36×10 + 6

θ = 366°

When n = 10 is out of range of θ

Then, the solution is from n =0 to n=9

So the equation have 10 solutions in the range 0<θ<2π

4 0
3 years ago
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