All categories

3 years ago

Use the graph to write an equation for the parabola. (Hard one)

Mathematics

1 answer:

borishaifa [10]3 years ago

6 0

Answer:

y = (10/9)x^2

Step-by-step explanation:

The vertex is at (0, 0), so the parent function is y=x^2 with no vertical or horizontal translation. A vertical scale factor can be used to make the graph go through the given points.

For x=3, the parent function gives ...

y = 3^2 = 9

The actual value you want is 10, so is a factor of (10/9) times the value you have. That is ...

10 = (10/9)×9

Applying this scale factor to the parent function gives you ...

y = (10/9)x^2

You might be interested in

Blue marlin can swim at speeds of about 50 miles per hour.What is that speed and feet per second to the nearest whole number

pentagon [3]

264000, 5280 feet in a mile, multiply by 50

6 0

4 years ago

Determine the unit of measurement that best represents each scenario.

BARSIC [14]

Answer:

pounds, ounces, tons

Step-by-step explanation:

7 0

2 years ago

Two integers have a sum of -11 and a difference of 5. What are the two

Rudiy27

Answer:

x = -3

y = -6

Step-by-step explanation:

x+y = -11

x-y = 5

x+y+x-y= -6

2x= -6

x = -3

y = -6

3 0

3 years ago

A = ???? 4 −2

irinina [24]

Answer:

1. The matrix A isn't the inverse of matrix B.

2. |B|=12, |A|=12

Step-by-step explanation:

1. We want to know if matrix A is the inverse of matrix B, this means that if you do the product between B and A you have to obtain the identity matrix.

We have:

$A=\left[\begin{array}{cc}4&-2\\-1&3\end{array}\right]$

and

$B=\left[\begin{array}{cc}3&2\\1&4\end{array}\right]$

A and B are 2×2 matrices (2 rows and 2 columns), if you multiply them you have to obtain a 2×2 matrix.

Then if A is the inverse of B:

$B.A=I$

Where,

$I=\left[\begin{array}{cc}1&0\\0&1\end{array}\right]$

Observation:

If you have two matrices:

$A=\left[\begin{array}{cc}a&b\\c&d\end{array}\right]\\and\\B=\left[\begin{array}{cc}e&f\\g&h\end{array}\right]\\\\\\A.B=\left[\begin{array}{cc}(a.e+b.g)&(a.f+b.h)\\(c.e+d.g)&(c.f+d.h)\end{array}\right]$

Now:

$B.A=\left[\begin{array}{cc}3&2\\1&4\end{array}\right].\left[\begin{array}{cc}4&-2\\-1&3\end{array}\right]\\\\\\B.A=\left[\begin{array}{cc}4.3+(-2).1&4.2+(-2).4\\(-1).3+3.1&(-1).2+3.4\end{array}\right]\\\\\\B.A=\left[\begin{array}{cc}12-2&8-8\\-3+3&-2+12\end{array}\right]\\\\\\B.A=\left[\begin{array}{cc}10&0\\0&10\end{array}\right]$