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Ksivusya [100]
2 years ago
8

Which TWO answers indicate why it's important to round numbers?

Mathematics
2 answers:
Scilla [17]2 years ago
6 0
I think that you're answers here would be:
~Sometimes it helps in estimating an answer
And
~<span>Calculations may lead to long decimals, but money is in dollars and cents.
</span>Hope this helps you, and happy studying~!
~Mistermistyeyed.
Anni [7]2 years ago
4 0
<span>-Calculations may lead to long decimals, but money is in dollars and cents.
-Looks neater</span>
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1) Let f(x)=6x+6/x. Find the open intervals on which f is increasing (decreasing). Then determine the x-coordinates of all relat
brilliants [131]

Answer:

1) increasing on (-∞,-1] ∪ [1,∞), decreasing on [-1,0) ∪ (0,1]

x = -1 is local maximum, x = 1 is local minimum

2) increasing on [1,∞), decreasing on (-∞,0) ∪ (0,1]

x = 1 is absolute minimum

3) increasing on (-∞,0] ∪ [8,∞), decreasing on [0,4) ∪ (4,8]

x = 0 is local maximum, x = 8 is local minimum

4) increasing on [2,∞), decreasing on (-∞,2]

x = 2 is absolute minimum

5) increasing on the interval (0,4/9], decreasing on the interval [4/9,∞)

x = 0 is local minimum, x = 4/9 is absolute maximum

Step-by-step explanation:

To find minima and maxima the of the function, we must take the derivative and equalize it to zero to find the roots.

1) f(x) = 6x + 6/x

f\prime(x) = 6 - 6/x^2 = 0 and x \neq 0

So, the roots are x = -1 and x = 1

The function is increasing on the interval (-∞,-1] ∪ [1,∞)

The function is decreasing on the interval [-1,0) ∪ (0,1]

x = -1 is local maximum, x = 1 is local minimum.

2) f(x)=6-4/x+2/x^2

f\prime(x)=4/x^2-4/x^3=0 and x \neq 0

So the root is x = 1

The function is increasing on the interval [1,∞)

The function is decreasing on the interval (-∞,0) ∪ (0,1]

x = 1 is absolute minimum.

3) f(x) = 8x^2/(x-4)

f\prime(x) = (8x^2-64x)/(x-4)^2=0 and x \neq 4

So the roots are x = 0 and x = 8

The function is increasing on the interval (-∞,0] ∪ [8,∞)

The function is decreasing on the interval [0,4) ∪ (4,8]

x = 0 is local maximum, x = 8 is local minimum.

4) f(x)=6(x-2)^{2/3} +4=0

f\prime(x) = 4/(x-2)^{1/3} has no solution and x = 2 is crtitical point.

The function is increasing on the interval [2,∞)

The function is decreasing on the interval (-∞,2]

x = 2 is absolute minimum.

5) f(x)=8\sqrt x - 6x for x>0

f\prime(x) = (4/\sqrt x)-6 = 0

So the root is x = 4/9

The function is increasing on the interval (0,4/9]

The function is decreasing on the interval [4/9,∞)

x = 0 is local minimum, x = 4/9 is absolute maximum.

5 0
2 years ago
Julio bought 7 science fiction novels (s) and 7 comic books c) from the bookstore. His purchases can be represented by the expre
ANTONII [103]

Answer:

$92.60

Step-by-step explanation:

7($5.99) + 7($6.49)=$41.93

$41.93 + $45.43  = $87.36

$87.36 + ($87.36 × 6%=0.06)

$87.36 + (0.06 × $87.36=5.24)

$87.36 + $5.24= $92.60

7 0
3 years ago
Graph the image of QRS after a rotation 270º counterclockwise around the origin.
sergij07 [2.7K]

Answer:

Q=(1,-5)

R=(5,-5)

S=(2,-7)

Step-by-step explanation:

8 0
3 years ago
Janna spends 1.25 hours of her 8 hour work day answering email messages. What percentage of the work day is this time
dusya [7]
1.25 divided by 8 =0.15635×100=15.6% or round up to 16%
3 0
2 years ago
The lines shown below are perpendicular. If the green line has a slope of
klasskru [66]

Answer: 4

Step-by-step explanation:

Perpendicular lines have reciprocal slopes

8 0
2 years ago
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