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allochka39001 [22]
3 years ago
6

A cup of brewed tea has 54 milligrams less caffeine than a cup of brewed coffee. If a cup of tea has 66 milligrams of caffeine,

how much caffeine is in a cup of coffee? Write this problem in an equation.
Mathematics
2 answers:
vfiekz [6]3 years ago
5 0
X-54= 66        x being the amount of caffeine in the cup of coffee.
topjm [15]3 years ago
3 0

Answer:

There is 120 milligrams of caffeine in a cup of coffee.

Step-by-step explanation:

A cup of brewed tea has 54 milligrams less caffeine than a cup of brewed coffee. A cup of tea has 66 milligrams of caffeine.

Let the amount of caffeine in a cup of coffee be = x

In the equation form, we can denote this as:

66=x-54

Solving for x

x=66+54

x = 120

Therefore, there is 120 milligrams of caffeine in a cup of coffee.

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9x - 7x2 +4x2 - x + 4x3 - 3x2
Anna35 [415]

Answer:

The answer to your question is:    4x³ - 6x² + 8x

Step-by-step explanation:

see the picture  

3 0
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Explain why 30 divided by x is the same as 30 -x-x-x-x-x-x equal 0
sattari [20]
The value would be zero (0) bcuz if all ends up being 0 no matter how many zeros then yes it would be 0 as the value
7 0
3 years ago
Is there a difference in the amount of airborne bacteria between carpeted and uncarpeted rooms? In an experiment, seven rooms we
Annette [7]

Answer:

C. There isn't much evidence to support a conclusion that the presence of carpet is associated with an increase or decrease in the mean bacterial concentration of air.

Step-by-step explanation:

A. There are outliers in these data, so we can't rely on the two-sample t test.

There are no outliers, as the seven rooms for both sample have similar size and function.

B. This test is unreliable because the populations we're sampling from are heavily skewed.

We don't know if the populations are heavily skewed, but this effect should be appeased by the sampling.

C. There isn't much evidence to support a conclusion that the presence of carpet is associated with an increase or decrease in the mean bacterial concentration of air.

Correct conclusion, as the P-value is surely greater than the significance level (usually 0.10 at most).

D. There is fairly strong evidence to support a conclusion that the presence of carpet is associated with an increase or decrease in the mean bacterial concentration of air.

There is no evidence as the P-value is greater than the significance level.

4 0
3 years ago
Hello can anyone please help me with this assignment it’s due tomorrow please and thanks !
snow_lady [41]

Answer:

PART 2,4,6 are not solvable since they do not have any number

Part 1

1 = 61

2 = 119

3 = 61

4 = 119

5 = 61

6 = 119

7 = 61

8 = 119

Part 3

1 = 128

2 = 52

3 = 128

4= 52

5 = 128

6 =52

7 = 128

8 =52

Part 5

1 = 135

2 = 45

3 = 135

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8 0
3 years ago
Find the moment of inertia about the y-axis of the thin semicirular region of constant density
arlik [135]

The moment of inertia about the y-axis of the thin semicircular region of constant density is given below.

\rm I_y = \dfrac{1}{8} \times \pi r^4

<h3>What is rotational inertia?</h3>

Any item that can be turned has rotational inertia as a quality. It's a scalar value that indicates how complex it is to adjust an object's rotational velocity around a certain axis.

Then the moment of inertia about the y-axis of the thin semicircular region of constant density will be

\rm I_x = \int y^2 dA\\\\I_y = \int x^2 dA

x = r cos θ

y = r sin θ

dA = r dr dθ

Then the moment of inertia about the x-axis will be

\rm I_x = \int _0^r \int _0^{\pi}  (r\sin \theta )^2  \ r \  dr \  d\theta\\\\\rm I_x = \int _0^r \int _0^{\pi}  r^3 \sin ^2\theta  \  dr \  d\theta

On integration, we have

\rm I_x = \dfrac{1}{8} \times \pi r^4

Then the moment of inertia about the y-axis will be

\rm I_y = \int _0^r \int _0^{\pi}  (r\cos\theta )^2  \ r \  dr \  d\theta\\\\\rm I_y = \int _0^r \int _0^{\pi}  r^3 \cos ^2\theta  \  dr \  d\theta

On integration, we have

\rm I_y = \dfrac{1}{8} \times \pi r^4

Then the moment of inertia about O will be

\rm I_o = I_x + I_y\\\\I_o = \dfrac{1}{8} \times \pi r^4 + \dfrac{1}{8} \times \pi r^4\\\\I_o = \dfrac{1}{4} \times \pi r^4

More about the rotational inertia link is given below.

brainly.com/question/22513079

#SPJ4

3 0
2 years ago
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