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3 years ago

Which do you think is the better estimate ?explain

Mathematics

1 answer:

ipn [44]3 years ago

7 0

A better estimate would be something that is closer to one you had before...

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Plssss help meeeee!!!!!!!!!!!!!!!!!!!

igomit [66]

Answer:

b = -30

Step-by-step explanation:

-b/5 - 27 = -21

~Add 27 to both sides

-1/5b = 6

~Multiply -5 to both sides

b = -30

Best of Luck!

8 0

3 years ago

______ an argument which convinces other people that something is true

Alina [70]

Answer:

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Segment BDSegment BD is a perpendicular bisector of segment ACsegment AC . AD=8x−15AD=8x−15 and DC=57DC=57 .

Charra [1.4K]

I hope this helps you

7 0

3 years ago

Read 2 more answers

Classify ABC by its sides. Then determine whether it is a right triangle.

m_a_m_a [10]

Answer:

∴Given Δ ABC is not a right-angle triangle

a= AB = √45 = 3√5

b = BC = 12

c = AC = √45 = 3√5

Step-by-step explanation:

Given vertices are A(3,3) and B(6,9)

$AB = \sqrt{x_{2}-x_{1} )^{2} +(y_{2}-y_{1} )^{2} }$

AB = $\sqrt{(9-3)^{2}+(6-3)^{2} } = \sqrt{6^{2}+3^{2} } =\sqrt{45}$

Given vertices are B(6,9) and C( 6,-3)

$B C = \sqrt{x_{2}-x_{1} )^{2} +(y_{2}-y_{1} )^{2} }$

= $\sqrt{(-3-9)^{2}+(6-6)^{2} } =\sqrt{12^{2} } = 12$

BC = 12

Given vertices are A(3,3) and C( 6,-3)

$AC = \sqrt{(6-3)^{2}+(-3-3)^{2} } = \sqrt{9+36} = \sqrt{45}$

AC² = AB²+BC²

45 = 45+144

45 ≠ 189

∴Given Δ ABC is not a right angle triangle

5 0

3 years ago

Please help me out with this!

kotykmax [81]

I don't really grab the concept of this but it's basically numbering the graph ang filling the coordinates in the x and y spaces
y=4/-2+ x=5/-3

7 0

3 years ago