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3 years ago

Find the value of the expression 3m^2+2p^2-15 when m =3 and p = 10

1 answer:

5 0

$3m {}^{2} + {2p}^{2} - 15$
m = 3
p = 10

$3 \times 3 {}^{2} + 2 \times {10}^{2} - 15 =$
$3 \times 9 + 2 \times 100 - 15 =$
$27 + 200 - 15 =$
$212$

Hence, the answer is 212.

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The cat weighs 14.375 pounds (or 230 ounces even).

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Solve for s. S + 3s - 4 = 16 S = Submit

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The answer is 5 because 16+4=20 and 3s + s = 4s so you’re left with 4s = 20 and I know that 4 times 5 is 20.
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⬆️ ⬆️ Question Please Help ☹

zysi [14]

Answer:

See the Venn diagram attached

Numbers given:

Total: 100
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Airida [17]

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2 years ago

Javier has four cylindrical models. The heights, radii, and diagonals of the vertical cross-sections of the models are shown in

Ronch [10]

The model in which the lateral surface meets the base at right angle is : Model 1.

<h3>What is a lateral surface?</h3>

The lateral surface of an object is all surfaces of that object excluding its base and top.

Analysis:

To know the exact model, we check for the models in which their dimensions form a Pythagorean triplet otherwise a right-angled triangle.

For Pythagorean triplet, the square of the diagonal must be equal to the sum of squares of the other two sides.

Model 1

Diagonal = 50cm, radius = 14cm, lateral height = 48cm

$(50)^{2}$ = $(14)^{2}$ + $(48)^{2}$

2500 = 196 + 2304

2500 = 2500. Forms Pythagorean triplet

Model 2

Diagonal= 37cm, radius = 6cm lateral height = 35cm

$(37)^{2}$ = $(35)^{2}$ + $(6)^{2}$

1369 = 1225 +36

1369 $\neq$ 1261

Model 3

Diagonal = 60cm, radius = 20cm lateral height = 40cm

$(60)^{2}$ = $(20)^{2}$ + $(40)^{2}$

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3600 $\neq$ 2000

Model 4

Diagonal = 30cm, radius = 24cm, lateral height = 9cm

$(30)^{2}$ = $(24)^{2}$ + $(9)^{2}$

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900 $\neq$ 657

Therefore the lateral surface model 1 meets the base at right angle

In conclusion, the lateral surface of model 1 meets the base at right angles as the dimensions form a right-angled triangle.

Learn more about Pythagorean triplet: brainly.com/question/20894813

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1 year ago

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