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Leno4ka [110]
3 years ago
14

The function f(x) = –2(x – 10)(x – 200) represents a company's monthly profit as a function of the number of items sold, x. What

is the maximum monthly profit?  $
Mathematics
1 answer:
Elodia [21]3 years ago
8 0
This function is a quadratic equation with a global maximum.

If you look carefully, the x-intercepts are x =10 and x = 200. Based on the characteristics of quadratic equation, the maximum lies in:

x = (10+200)/ 2 = 105

Then, you sub x = 105 into the equation, you will get the maximum profit:

f(105) = 18050
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Step-by-step explanation:

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t=\dfrac{-b\pm \sqrt{b^2-2ac} }{2a}\\\\t=\dfrac{-b+ \sqrt{b^2-2ac} }{2a},\dfrac{-b- \sqrt{b^2-2ac} }{2a}\\\\t=\dfrac{-32+ \sqrt{(32)^2-2\times (-16)(8)} }{2\times (-16)},\dfrac{-32-\sqrt{(32)^{2}-2\times(-16)(8)}}{2\times(-16)}\\\\t=-0.11\ s, 2.11\ s

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