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3 years ago

What are the next two numbers in this pattern? 3, –9, 27, –81, . . .

Mathematics

2 answers:

Romashka [77]3 years ago

8 0

Divide -81 by 27. You get -3.

Divide 27 by -9. You get -3.

Divide -9 by 3. You get -3.

Every new term is the previous term multiplied by -3.

Multiply -81 by -3: -81 * (-3) = 243

Multiply 243 by -3: -3 * 243 = -729

Answer: 243, -729

SVEN [57.7K]3 years ago

7 0

I believe it is 243 and -738

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What fraction is equal to 66?

marysya [2.9K]

The fraction equal to .66 is 33⁄50

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3 years ago

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Using the given postulate, tell which parts of the pair of triangles should be shown congruent.

weqwewe [10]

Answer:

it should be the 5th one because it shows defencicy

Step-by-step explanation:

from what i know

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2 years ago

Help me please fast

Natalija [7]

Answer:

Step-by-step explanation:

$\frac{5}{x-3}+\frac{2}{x+1}=3 \\\\\frac{5(x+1)+2(x-3)}{(x-3)(x+1)} =3\\\\5x+5+2x-6=3(x-3)(x+1)\\\\7x-1=3(x^2+x-3x-3)\\\\7x-1=3(x^2-2x-3)\\\\7x-1=3x^2-6x-9\\\\0=3x^2-6x-7x-9+1\\0=3x^2-13x-8$

Hence proved!

3 0

3 years ago

2. In a school of 320 students, 85 students are in the band, 200 students are on sports teams, and 60 students

Alja [10]

Answer:

60 students are involved in either band or sports.

95 students are not involved in either sports or band.

Step-by-step explanation:

Given:

In a school of 320 students, 85 students are in the band, 200 students are on sports teams, and 60 students participate in both activities.

Now, to find the students are involved in either sports or band. And students who are not involved in either sports or band.

Total number of students = 320.

Number of students in the band = 85.

Number of students in the sports team = 200.

Number of students participate in both activities = 60.

Thus, 60 students are involved in either band or sports.

So, the number of students in the band adding number of students in the sports team we get:

200 + 85 = 285.

Then, to subtract the number of students participate in both activities we get:

285 - 60 = 225.

Thus, the remaining students are = 225.

Now, to get the students who are not involved in either sports or band we subtract the total number of students from the remaining students:

$320-225$

$=95.$

Therefore, 60 students are not involved in either band or sports. 95 students are not involved in either sports or band.

8 0

3 years ago

Brainliest to first correct answer

Artyom0805 [142]

Answer:

Smallest surface area is of Cuboid B i.e 440 cm²

So, The company will choose cuboid B

Step-by-step explanation:

We need to find the surface area of all cuboids.

Surface Area of Cuboid A:

Length = 6

Breadth = 25

Height = 4

The formula used is: $Surface \ Area \ of \ Cuboid=2((Length\times Breadth)(Breadth \times Height)+(Length \times Height)$

Putting values and finding surface area:

$Surface \ Area \ of \ Cuboid=2((Length\times Breadth)(Breadth \times Height)+(Length \times Height)\\Surface \ Area \ of \ Cuboid=2((6 \times 25)+(25 \times 4)+(6 \times 4))\\Surface \ Area \ of \ Cuboid=2(150+100+24)\\Surface \ Area \ of \ Cuboid=2(274)\\Surface \ Area \ of \ Cuboid=548\: cm^2$

So, Surface Area of Cuboid A = 548 cm²

Surface Area of Cuboid B:

Length = 10

Breadth = 6

Height = 10

The formula used is: $Surface \ Area \ of \ Cuboid=2((Length\times Breadth)(Breadth \times Height)+(Length \times Height)$

Putting values and finding surface area:

$Surface \ Area \ of \ Cuboid=2((Length\times Breadth)(Breadth \times Height)+(Length \times Height)\\Surface \ Area \ of \ Cuboid=2(10 \times 6)+(6 \times 10)+(10 \times 10))\\Surface \ Area \ of \ Cuboid=2(60+60+100)\\Surface \ Area \ of \ Cuboid=2(220)\\Surface \ Area \ of \ Cuboid=440\: cm^2$

So, Surface Area of Cuboid B = 440 cm²

Surface Area of Cuboid C:

Length = 2

Breadth = 20

Height = 15

The formula used is: $Surface \ Area \ of \ Cuboid=2((Length\times Breadth)(Breadth \times Height)+(Length \times Height)$

Putting values and finding surface area:

$Surface \ Area \ of \ Cuboid=2((Length\times Breadth)(Breadth \times Height)+(Length \times Height)\\Surface \ Area \ of \ Cuboid=2((2 \times 20)+(20 \times 15)+(2 \times 15))\\Surface \ Area \ of \ Cuboid=2(40+300+30)\\Surface \ Area \ of \ Cuboid=2(370)\\Surface \ Area \ of \ Cuboid=740\: cm^2$

So, Surface Area of Cuboid C = 740 cm²

So, We get:

Surface Area of Cuboid A = 548 cm²

Surface Area of Cuboid B = 440 cm²

Surface Area of Cuboid C = 740 cm²

The company wants to choose the design having smallest surface area.

So, smallest surface area is of Cuboid B i.e 440 cm²

So, The company will choose cuboid B

5 0

3 years ago