All categories

3 years ago

What are skew lines

2 answers:

5 0

Answer: Skew lines are two lines that do not intersect and are not parallel. A simple example of a pair of skew lines is the pair of lines through opposite edges of a regular tetrahedron.

Julli [10]3 years ago

5 0

Skew lines are lines that do not intersect and that are not parallel

You might be interested in

How to find the rate in exponential growth formula A=P(1-r)^t

erma4kov [3.2K]

R = rate
A = P(1-r)^t
A^t = P(1-r)
A^t/P = 1-r
(A^t/P)-1 = -r
r = -((A^t/P)-1)

8 0

3 years ago

A line passes through the points (1, 4) and (3, –4). Which is the equation of the line?

horsena [70]

Answer:

The equation of line passing through points (1 , 4) and (3 , - 4) is y = - 4 x + 8

Step-by-step explanation:

Given as :

A line is passing through points

$x_1$ , $y_1$ = 1 , 4

$x_2$ , $y_2$ = 3 , - 4

Now, Equation of line in point-slope form is

y - $y_1$ = m × (x - $x_1$ )

where m is the slope of line

∵ m = $\dfrac{y_2 - y_1}{x_2 - x_1}$

i.e m = $\dfrac{ ( - 4 ) - 4}{3 - 1}$

Or, m = $\dfrac{ - 8}{2}$

Or, m = - 4

So, The slope of line = m = - 4

∵, equation of line can be written as

y - $y_1$ = m × (x - $x_1$ )

So, Putting the value of slope, m and points ( $x_1$ , $y_1$ )

i.e y - 4 = ( - 4 ) × ( x - 1 )

Or, y - 4 = ( - 4 ) × x + 4

Or, y - 4 = - 4 x + 4

Or, y = - 4 x + 4 + 4

∴ y = - 4 x + 8

So, The equation of line y = - 4 x + 8

Hence, The equation of line passing through points (1 , 4) and (3 , - 4) is y = - 4 x + 8 Answer

8 0

3 years ago

Read 2 more answers

Find the exponential function that satisfies the given conditions: Initial value = 37, increasing at a rate of 5% per year

beks73 [17]

The required function is:

Option 3: $f(t) = 37. (1.05)^t$

Step-by-step explanation:

The initial value and rate is used to write exponential function

Here

Given

Initial value = 37

Rate = r = 5%

When the rate is 5%, the next year the quantity will be 1+0.05 = 1.05 time of the current quantity.

So,

The function can be written as:

$f(t) = 37. (1.05)^t$

For initial value, put t=0

$f(t) = 37. (1.05)^0\\f(t) = 37 * 1\\f(t) = 37$

Hence,

The required function is:

Option 3: $f(t) = 37. (1.05)^t$

Keywords: Functions, exponential functions

Learn more about functions at:

#LearnwithBrainly

4 0

3 years ago

Perform the indicated operation. f(x) = x^3 + 5x g(x) = 4x Find (f . g)(x)

cestrela7 [59]

Step-by-step explanation:

$f(x) = {x}^{3} + 5x \\ g(x) = 4x \\ \\ \therefore \: (f.g)(x) = f(x) . g(x) \\ = ( {x}^{3} + 5x ).4x \\ = {x}^{3} .4x + 5x.4x \\ \red{{ \boxed{\bold{\therefore \: (f.g)(x) = 4 {x}^{4} + 20 {x}^{2} }}}}$