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3 years ago

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Christopher's back yard is in the shape of a trapezoid. The bases of his back yard are 30 and 40 feet long. The area of his back

yard is 525 square feet. Write and solve an equation to find the height of Christopher's back yard.

1 answer:

quester [9]3 years ago

4 0

Answer:

15 feet

Step-by-step explanation:

525 = ½(30+40)h

525 = 35h

h = 525/35

h = 15 feet

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Please help me with this. Just have to write the equation. If you can solve, then you get brainliest guaranteed!

Temka [501]

x = player1

y = player 2

z = player 3

y = 2x or 1/2 y =x

y = z-10 or z = y+10

x+y+z=70

substitute x= 1/2 y and z = y+10 into the above equation

1/2y + y + y+10 = 70

2.5 y + 10 = 70

subtract 10 from each side

2.5 y = 60

divide by 2.5 on each side

y = 60/2.5

y =24

x = 1/2 y

x = 1/2 *24 = 12

z = y+10 = 24+10 = 34

The three players scored 12, 24, 34

4 0

3 years ago

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A toy box has a volume of 30 cubic feet. It is 5 feet wide And 2 feet long. What is the height of the toy box

otez555 [7]

V = a * b * c
V = 30
a = 5
b = 2
c = ?
30 = 5*2*c
30 = 10*c
c = 30/10 = 3
c = 3

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3 years ago

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Graph 24x+25=−6y+7 .

MrRa [10]

Okay, So you have 24x+25=6y+7

Step 1: Pull out like factors : 24x + 18 + 6y = 6 • (4x + y + 3)

Step 2: 4x+y+3 = 0

y-intercept = -3/1 = -3.00000

x-intercept = -3/4 = -0.75000

Slope = -8.000/2.000 = -4.000

And bam, you have a straight line

5 0

3 years ago

30 points!!<br> What is the sum of the first six terms of the series?<br> 48 - 12 + 3 - 0.75 +...

Lunna [17]

Answer:

The sum of the first six terms is 38.39

Step-by-step explanation:

This is a geometric sequence since the common difference between each term is $-\frac{1}{4}$

Thus, $r=-\frac{1}{4}$

To find the sum of first six terms, we need to find the fifth and sixth term of the sequence.

To find the fifth term:

The general form of geometric sequence is $a_{n}=a_{1} \cdot r^{n-1}$

To find the fifth term, substitute $n=5$ in $a_{n}=a_{1} \cdot r^{n-1}$

$\begin{aligned}a_{5} &=(48) \cdot\left(-\frac{1}{4}\right)^{5-1} \\&=(48) \cdot\left(-\frac{1}{4}\right)^{4} \\&=(48)\left(\frac{1}{256}\right) \\a_{5} &=0.1875\end{aligned}$

To find the sixth term, substitute $n=6$ in $a_{n}=a_{1} \cdot r^{n-1}$

$\begin{aligned}a_{6} &=(48) \cdot\left(-\frac{1}{4}\right)^{6-1} \\&=(48) \cdot\left(-\frac{1}{4}\right)^{5} \\&=(48)\left(-\frac{1}{1024}\right) \\a_{5} &=-0.046875\end{aligned}$

To find the sum of the first six terms:

The general formula to find Sn for $|r|$ is $S_{n}=\frac{a\left(1-r^{n}\right)}{1-r}$

$\begin{aligned}S_{6} &=\frac{48\left(1-\left(-\frac{1}{4}\right)^{6}\right)}{1-\left(-\frac{1}{4}\right)} \\&=\frac{48\left(1-\frac{1}{4096}\right)}{1+\frac{1}{4096}} \\&=\frac{48(0.95)}{5} \\&=\frac{48(0.9998)}{5} \\&=\frac{48(0.9998)}{5} \\&=\frac{47.9904}{5} \\&=38.39\end{aligned}$

Thus, the sum of first six terms is 38.39

5 0

3 years ago

Please help!!!!

tatyana61 [14]

Answer:

Step-by-step explanation:

From the figure attached,

If the figures shown are congruent (Equal in shape and size), length of all the sides must be equal.

Therefore, sides sides CD and GH must be equal in measures.

Distance between the two points $(x_1,y_1)$ and $(x_2,y_2)$ is given by,

d = $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Length of the side CD having ends C(-4, 4) and D(0, 5) will be,

CD = $\sqrt{(-4-0)^2+(4-5)^2}$

CD = $\sqrt{(16+1)}$

= $\sqrt{17}$

Length of GH having ends G(0, -4) and H(4, -5) will be,

GH = $\sqrt{(0-4)^2+(-4+5)^2}$

= $\sqrt{16+1}$

= $\sqrt{17}$

Therefore, m(CD) = m(GH)

Similarly, we can prove all corresponding sides of two figures equal in measure.

This shows ABCD ≅ EFGH.

3 0

3 years ago