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Free_Kalibri [48]
3 years ago
10

Can someone help me on this question please

Mathematics
2 answers:
umka21 [38]3 years ago
7 0
I THINK the answer is 5.
pochemuha3 years ago
5 0

Yeah the answer IS 5.
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Expand (3x + 1)(x + 2) using the box method of by foiling. Show or explain<br> your steps.
Reika [66]
The result would be 3x^2+7x+2.

If you have any question, tell me and I would be more than happy to help! Thanks.
3 0
3 years ago
I don’t know how to make a rule:(
Yuri [45]

Answer:

*assuming you know the concept of proportionality*

since L is directly proportional to T, an increase in L will result in an increase in T

so the solution of the first part is increases

in part 2, y is inversely proportional to x

which means that an increase in y will result in a decrease in x and vice-versa

So the answer of the second part is decreases

in part 3, since x is directly proportional to y, an increase in x will result in an increase in y

8 0
3 years ago
A library subscribes to two different weekly news magazines, each of which is supposed to arrive in Wednesday�s mail. In actuali
Softa [21]

Answer:

P(Y = 0) = 0.09

P(Y = 1) = 0.4

P(Y = 2) = 0.32

P(Y = 3) = 0.19

Step-by-step explanation:

Let the events be:

W = Wednesday

T = Thursday

F = Friday

S = Saturday

Their corresponding probabilities are

P(W) = 0.3\\P(T) = 0.4\\P(F) = 0.2\\P(S) = 0.1

Since Y = number of days beyond Wednesday that it takes for both magazines to arrive(so possible Y values are 0, 1, 2 or 3)

The possible number of outcomes are therefore 4^2 = 16\\(W, W), (W, T), (W, F), (W, S)\\(T, W), (T, T), (T, F), (T, S)\\(F, W), (F, T), (F, F), (F, S)\\(S, W), (S, T), (S, F), (S, S)

The values associated for each of the outcomes are as follows:

Y(W, W) = 0, Y(W, T) = 1, Y(W, F) = 2, Y(W, S) = 3\\Y(T, W) = 1, Y(T, T) = 1, Y(T, F) = 2, Y(T, S) = 3\\Y(F, W) = 2, Y(F, T) = 2, Y(F, F) = 2, Y(F, S) = 3\\Y(S, W) = 3, Y(S, T) = 3, Y(S, F) = 3, Y(S, S) = 3

The probability mass function of Y is,

P(Y = 0) = 0.3(0.3) = 0.09\\P(Y = 1) = P[(W, T) or (T, W) or (T, T)]\\= [0.3(0.4) + 0.3(0.4) + 0.4(0.4)]\\= 0.4\\\\P(Y = 2) = P[(W, F) or (T, F) or (F, W) or (F, T) or (F, F)]\\= [0.3(0.2) + 0.4(0.2) + 0.2(0.3) + 0.2(0.4) + 0.2(0.2)]\\= 0.32\\\\P(Y = 3) = P[(W, S) or (T, S) or (F, S) or (S, W) or (S, T) or (S, F) or (S, S)]\\= [0.3(0.1) + 0.4(0.1) + 0.2(0.1) + 0.1(0.3) 0.1(0.4) + 0.1(0.2) + 0.1(0.1)]\\= 0.19

7 0
3 years ago
Russia has recently started a push for stronger smoking regulations much like those in western countries concerning cigarette ad
Blababa [14]

Answer:

a) 0.46

b) (2341.39, 3230.61)

c) For those Russians who do smoke, estimate the number of cigarettes smoked per day.= 23

Step-by-step explanation:

check below for more detailed solution

7 0
3 years ago
The scale on a map is 2 cm= 5.5 miles. If two cities are 15 miles apart, how many cm apart would they be on the map?
xxTIMURxx [149]

Answer:

3 cm

Step-by-step explanation:

5 0
3 years ago
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