The standard equation of a circle is given by:
(x-a)²+(y-b)²=r²
where:
(a,b) is the center and r is the radius.
Given that (a,b) is (-8,-3) and r=2 units
then the equation of the circle will be:
(x-(-8))²+(y-(-3))²=2²
simplifying the above we get:
(x+8)²+(y+3)²=4
Answer:
d. quadrilateral
Step-by-step explanation:
Answer:
y=79/73x+644/73
theres the equation, enjoy <3
Given:
Base area = 4π mm²
Height = 10 mm
To find:
The volume of the cylinder.
Solution:
Base of the cylinder is circle.
Area of the base = πr²
πr² = 4π
Volume of the cylinder = πr²h
Substitute 4π in place of πr².
= 4π × 10
= 40π mm³
The volume of the cylinder is 40π mm³.
Answer:
4 = 22
Step-by-step explanation:
Factor 40 into its prime factors
40 = 23 • 5
To simplify a square root, we extract factors which are squares, i.e., factors that are raised to an even exponent.
Factors which will be extracted are :
4 = 22
Factors which will remain inside the root are :
10 = 2 • 5
To complete this part of the simplification we take the squre root of the factors which are to be extracted. We do this by dividing their exponents by 2 :
2 = 2
At the end of this step the partly simplified SQRT looks like this:
2 • sqrt (10x4)
Rules for simplifing variables which may be raised to a power:
(1) variables with no exponent stay inside the radical
(2) variables raised to power 1 or (-1) stay inside the radical
(3) variables raised to an even exponent: Half the exponent taken out, nothing remains inside the radical. examples:
(3.1) sqrt(x8)=x4
(3.2) sqrt(x-6)=x-3
(4) variables raised to an odd exponent which is >2 or <(-2) , examples:
(4.1) sqrt(x5)=x2•sqrt(x)
(4.2) sqrt(x-7)=x-3•sqrt(x-1)
Applying these rules to our case we find out that
SQRT(x4) = x2
sqrt (40x4) =
2 x2 • sqrt(10)
Simplified Root :
2 x2 • sqrt(10)
