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Vladimir [108]
3 years ago
7

What's the difference?

Mathematics
1 answer:
lbvjy [14]3 years ago
8 0
The one above has parenthesis and the one below doesn't!!

Hope this helps!!! :D
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Round 75391 to the nearest ten
cluponka [151]
75390
7 is in the ten thousand place
5 is in the thousand place
3 is in the hundreds place
9 is in the tens place
1 is in the ones place
8 0
3 years ago
Read 2 more answers
Help pls I will give brainliest!
oee [108]

Answer:

We are missing 210

Step-by-step explanation:

3*4 = 12

3*70 =210

3*300=900

We are missing 210

8 0
3 years ago
Read 2 more answers
3. Problem 2: Suppose a radio manufacturer has the total cost function C (x) = 43x + $ 1850 and the revenue function R (x) = $ 8
OLEGan [10]

Given that,

Total cost function, C (x) = 43x + $1850

The revenue function R (x) = $80x

To find,

The number of units that must be produced and sold to break even.

Solution,

At break even, cost = revenue

43x + $1850 = $80x

Subtract 80x from both sides.

43x + 1850 -80x = $80x -80x

1850 = 80x-43x

37x = 1850

x = 50

So, the required number of units are 50.

8 0
3 years ago
PLZ HELP!!! Use limits to evaluate the integral.
Marrrta [24]

Split up the interval [0, 2] into <em>n</em> equally spaced subintervals:

\left[0,\dfrac2n\right],\left[\dfrac2n,\dfrac4n\right],\left[\dfrac4n,\dfrac6n\right],\ldots,\left[\dfrac{2(n-1)}n,2\right]

Let's use the right endpoints as our sampling points; they are given by the arithmetic sequence,

r_i=\dfrac{2i}n

where 1\le i\le n. Each interval has length \Delta x_i=\frac{2-0}n=\frac2n.

At these sampling points, the function takes on values of

f(r_i)=7{r_i}^3=7\left(\dfrac{2i}n\right)^3=\dfrac{56i^3}{n^3}

We approximate the integral with the Riemann sum:

\displaystyle\sum_{i=1}^nf(r_i)\Delta x_i=\frac{112}n\sum_{i=1}^ni^3

Recall that

\displaystyle\sum_{i=1}^ni^3=\frac{n^2(n+1)^2}4

so that the sum reduces to

\displaystyle\sum_{i=1}^nf(r_i)\Delta x_i=\frac{28n^2(n+1)^2}{n^4}

Take the limit as <em>n</em> approaches infinity, and the Riemann sum converges to the value of the integral:

\displaystyle\int_0^27x^3\,\mathrm dx=\lim_{n\to\infty}\frac{28n^2(n+1)^2}{n^4}=\boxed{28}

Just to check:

\displaystyle\int_0^27x^3\,\mathrm dx=\frac{7x^4}4\bigg|_0^2=\frac{7\cdot2^4}4=28

4 0
3 years ago
A soup can and label are shown. The label wraps around the circumference of the cylindrical can.
den301095 [7]

Answer: i would say 60 cm sorry if im wrong i think your missing a number

Step-by-step explanation:

4 0
3 years ago
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