Consider the quadratic function f(x) = x2 – 8x – 4. What is the value of the leading coefficient? –8 –4 0 1
2 answers:
Answer:
1 is leading coefficient. last option is correct
Explanation:
We have been given the quadratic function
We know that leading coefficient is the coefficient of the variable having highest exponent.
So, in order to state the leading coefficient we first of all find the highest exponent of the given function.
Clearly, the given function is quadratic and hence, the highest exponent is 2.
The coefficient of the variable of highest exponent is 1.
Therefore the leading coefficient is 1. last option is correct
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Suggesting that you want this in standard form, in terms of quadratic equations, you would technically follow a process similar if not almost exactly like the 2 - step equation method with the exception of separating the (x)s and the equations to find x and then plug it in and what-not.
With that being said you would subtract 5 in (x+5) from said 5 in the second equation and -10 in the first equation in order to get 2x^2+7x-15, you would continue to do the same for the x by subtracting it from both ends making the 7x a 6x because there is a 1 at the beginning of each x if there is no number that is shown already. Which finally gives you the equation (y= 2x^2+6x-15)
Suggesting that you want this in standard form, in terms of quadratic equations, you would technically follow a process similar if not almost exactly like the 2 - step equation method with the exception of separating the (x)s and the equations to find x and then plug it in and what-not.
With that being said you would subtract 5 in (x+5) from said 5 in the second equation and -10 in the first equation in order to get 2x^2+7x-15, you would continue to do the same for the x by subtracting it from both ends making the 7x a 6x because there is a 1 at the beginning of each x if there is no number that is shown already. Which finally gives you the equation (y= 2x^2+6x-15)