-3x+9 = -3(2x+3) + 3(x-4)+1
distribute
-3x+9 =-6x-9+3x-12+1
add like terms
-3x+9= -3x-20
add 3x to each side
9 = -20
there are no solutions because 9 does not equal -20
Answer:
a) e
b) c
c) a
Step-by-step explanation: Look at the number line. 0 shows that it has no probability while C is at 1/2 showing that it could be half-half. Then you can see one under E which means it is bound to happen.
Answer:
<u>t = t₀ - 3n</u>
Step-by-step explanation:
Let t be the temperature and t₀ be the initial temperature of the day
Let n be the number of hours after the initial temperature ( t₀) was registered
Let -3 be the constant of change of temperature ( In 4 hours it went down 12 degrees)
Now, let's write down the expression that shows the temperature change each hour, this way:
t = t₀ - 3n
After 2 hours
t = t₀ - 3 * 2 = t₀ - 6
After 5 hours
t = t₀ - 3 * 5 = t₀ - 15
After 3 hours and 30 minutes
t = t₀ - 3 * 3.5 = t₀ - 10.5
Let h represent the height of the trapezoid, the perpendicular distance between AB and DC. Then the area of the trapezoid is
Area = (1/2)(AB + DC)·h
We are given a relationship between AB and DC, so we can write
Area = (1/2)(AB + AB/4)·h = (5/8)AB·h
The given dimensions let us determine the area of ∆BCE to be
Area ∆BCE = (1/2)(5 cm)(12 cm) = 30 cm²
The total area of the trapezoid is also the sum of the areas ...
Area = Area ∆BCE + Area ∆ABE + Area ∆DCE
Since AE = 1/3(AD), the perpendicular distance from E to AB will be h/3. The areas of the two smaller triangles can be computed as
Area ∆ABE = (1/2)(AB)·h/3 = (1/6)AB·h
Area ∆DCE = (1/2)(DC)·(2/3)h = (1/2)(AB/4)·(2/3)h = (1/12)AB·h
Putting all of the above into the equation for the total area of the trapezoid, we have
Area = (5/8)AB·h = 30 cm² + (1/6)AB·h + (1/12)AB·h
(5/8 -1/6 -1/12)AB·h = 30 cm²
AB·h = (30 cm²)/(3/8) = 80 cm²
Then the area of the trapezoid is
Area = (5/8)AB·h = (5/8)·80 cm² = 50 cm²
First, get common denominators
At the same time, turn these into mixed numbers
27/8 + x = 44/8
Subtract 27/8 from both sides
x = 2 1/8 pounds
Let’s x be how many more pounds the baby needs