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Rama09 [41]
4 years ago
12

The table below represents a linear function f(x) and the equation represents a function g(x):

Mathematics
1 answer:
Paul [167]4 years ago
5 0

Answer:

Step-by-step explanation:

If you want to compare the 2 slopes, you first have to know what they are.  From the table we can find it by plugging in some numbers to the slope formula and doing the math on it:

m=\frac{-10-(-15)}{0-(-1)}

which gives us a slope of 5.

From the equation, which is in y = mx + b form, m stands for slope.  The number in the m position is 2.  In a sentence:

The slope found in the values from the table, 5, is greater than the slope found in the linear equation, 2.

Part B:  The y-intercept exists where x = 0.  Looking at the values in the table, where x = 0, y = -10.  So the y-intercept of the line in the table is -10.  In y = mx + b, the linear equation, 8 = b, which is also the y-intercept.  So the y-intercept in the table is -10 and the y-intercept in the equation is 8.  The y-intercept is greater in the equation than in the table because 8 is greater than -10

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Answer:

<h3>The statements i) x+y=y+x</h3><h3> ,iv) (x+y)+z=x+(y+z)</h3><h3>and v) (x-y)-z = x-(y-z) are true </h3>

Step-by-step explanation:

Given that  x = a + bi and y = c + di and z = f + gi

<h3>To check which statements are true :</h3><h3>i)x+y=y+x</h3><h3>Taking LHS x+y</h3>

Substitute the values of x and y we get

x+y=a+bi+c+di

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Substitute the values of x and y we get

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Substitute the values of x ,y and z we get

(x+y)+z=(a+bi+c+di)+(f+gi)

<h3>(x+y)+z=(a+c+f)+(b+d+g)i=LHS</h3><h3>Taking RHS x+(y+z)</h3>

Substitute the values of x ,y and z we get

x+(y+z)=(a+bi)+(c+di+f+gi)

<h3>x+(y+z)=(a+c+f)+(b+d+g)i=RHS</h3>

Therefore LHS=RHS

<h3>Therefore  statement (x+y)+z=x+(y+z) is true</h3><h3>v) (x-y)-z = x-(y-z)</h3><h3>Taking LHS (x-y)-z</h3>

Substitute the values of x ,y and z we get

(x-y)-z=(a+bi-(c+di))-(f+gi)

=a+bi-c-di-f-gi

<h3>(x-y)-z=(a-c-f)+(b-d-g)i=LHS</h3><h3>Taking RHS x+(y+z)</h3>

Substitute the values of x ,y and z we get

x-(y-z)=(a+bi)-((c+di)-(f+gi))

x-(y-z)=a+bi-c-di-f-gi=RHS

Therefore LHS=RHS

<h3>Therefore  statement (x-y)-z=x-(y-z) is true</h3><h3>Therefore the statements i) ,iv) and v) are true </h3><h3 />
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