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Vladimir79 [104]
3 years ago
13

A cereal packaging machine can fill 15 oz boxes at a rate of 3 boxes every 2 minutes. Production has scheduled 600 lbs to be pro

cessed during each 8-hour shift. Approximately how many minutes of down time will the machine have during each shift?
Mathematics
1 answer:
Pani-rosa [81]3 years ago
6 0

Answer:

53.33 minutes

Step-by-step explanation:

1 lb = 16 oz

600 x 16 = 9600

600 lbs = 9600 oz every 8 hours needed

15 x 3 = 45 oz every 2 minutes produced

45 / 2 = 22.5 oz every 1 minute procuded

8 x 60 = 480 minutes in 8 hours

9600 = 22.5x   =  9600 / 22.5 = 426.67 minutes until complete

480 - 426.67 = 53.33 minutes of downtime

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Answer: B

Because it does not pass through (0,0)

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How much is 5/6 times 2 3/4
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5/6 x 2 3/4 = 5/6 x (2x4+3)/4 = 5/6 x 11/4 = 55/24 = 2 7/24
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I have 31 stamps in total. I have 4 more 1 cent stamps than 8 cent stamps and twice as many one cent stamps as 12 cent stamps. I
Neko [114]

Answer:

There area 14 one cent stamps

Step-by-step explanation:

Let

x -----> the number of 1 cent stamps

y -----> the number of 8 cent stamps

z -----> the number of 12 cent stamps

we know that

0.01x+0.08y+0.12z=1.78 -------> equation A

x=y+4 ------> y=x-4 -----> equation B

x=2z -----> z=0.5x ------> equation C

substitute equation B and equation C in equation A and solve for x

0.01x+0.08(x-4)+0.12(0.5x)=1.78

0.01x+0.08x-0.32+0.06x=1.78

0.15x=1.78 +0.32

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x=14

therefore

There area 14 one cent stamps

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3 years ago
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Oliga [24]

Answer:

Part A)

The height of the water level in the rectangular vessel is 2 centimeters.

Part B)

4000 cubic centimeters or 4 liters of water.

Step-by-step explanation:

We are given a cubical vessel that has side lengths of 10cm. The vessel is completely filled with water.

Therefore, the total volume of water in the cubical vessel is:

V_{C}=(10)^3=1000\text{ cm}^3

This volume is poured into a rectangular vessel that has a length of 25cm, breadth of 20cm, and a height of 10cm.

Therefore, if the water level is h centimeters, then the volume of the rectangular vessel is:

V_R=h(25)(20)=500h\text{ cm}^3

Since the cubical vessel has 1000 cubic centimeters of water, this means that when we pour the water from the cubical vessel into the rectangular vessel, the volume of the rectangular vessel will also be 1000 cubic centimeters. Hence:

500h=1000

Therefore:

h=2

So, the height of the water level in the rectangular vessel is 2 centimeters.

To find how how much more water is needed to completely fill the rectangular vessel, we can find the maximum volume of the rectangular vessel and then subtract the volume already in there (1000 cubic centimeters) from the maximum volume.

The maximum value of the rectangular vessel is given by :

A_{R_M}=20(25)(10)=5000 \text{ cm}^3

Since we already have 1000 cubic centimeters of water in the vessel, this means that in order to fill the rectangular vessel, we will need an additional:

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Sincer 1000 cubic centimeters is 1 liter, this means that we will need four more liters of water in order to fill the rectangular vessel.

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Jika sin x = p, dengan x tumpul, maka cos(x + 60) =​
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Menjawab:

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Penjelasan langkah demi langkah:

Dari identitas trigonometri, pemuaiannya benar:

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Temukan KPK tersebut

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