Find the minimum, first quartile, median, third quartile, and maximum of each data set, 12, 10, 11, 7, 9, 10, 5
Sliva [168]
To find the median:
Least to greatest order:
5, 7, 9, 10, 10, 11, 12
10 is the number in the middle. Therefore the median is 10
The required diagram is attached in the picture below :
Answer:
15.05 miles
2 :09:12
5 hours 19 minutes 18 seconds
Step-by-step explanation:
Given :
28/4/18:
Time : 1 :03 : 25
Fastest mile = 02 : 25
Distance = 15.05 miles
03/5/18:
Time : 2:06: 41
Fastest mile = 02 : 53
Distance = 28.70 miles
08/5/18:
Time : 2 :09:12
Fastest mile = 02 : 45
Distance = 26.39 miles2
1.) shortest distance cycled :
From the data:
15.05 < 26.39 < 28.70
Shortest distance cycled = 15.05 miles
The longest the cycled:
1 :03 : 25 < 2:06: 41 < 2 :09:12
Longest = 2 :09:12
Total cycling time :
1 :03 : 25 + 2:06: 41 + 2 :09:12
(1 + 2 + 2)= 5 hrs
(03 + 06+ 09) = 18 minutes
(25 + 41 + 12) = 78 seconds = 1 minute 18 seconds
18 minutes + 1 minute = 19 minutes
Total = 5 hours 19 minutes 18 seconds
Answer: 36
Step-by-step explanation:
6/2= 3 & 3x2=6 & 27/9=3 & 3x9=27 so you would multiply 3x12=36 so you would just multiply. and I'm a 6th grader.
15.69 because 49.57-2.50 divided by 3 =15.69
Answer:
1
Step-by-step explanation: