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blondinia [14]
3 years ago
15

The straight line P has the equation y= 2x-5

Mathematics
1 answer:
Sunny_sXe [5.5K]3 years ago
4 0

Answer:

y=−x/2+2.

Step-by-step explanation:

The equation of the line in the slope-intercept form is y=2x−5.

The slope of the perpendicular line is negative inverse: m=−12.

So, the equation of the perpendicular line is y=−x/2+a.

To find a, we use the fact that the line should pass through the given point: 3=(−12)⋅(−2)+a.

Thus, a=2.

Therefore, the equation of the line is y=−x/2+2.

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Write an equation for a line parallel to y=−4x+5 and passing through the point (4,-21)
Sindrei [870]

Answer:

Y=-4x-5

Step-by-step explanation:

-21=-4(4)+b

-21=-16+b

b=-5

y=-4x-5

3 0
3 years ago
Read 2 more answers
What is the answer to this problem? 7(g+5)=105
Liono4ka [1.6K]

Answer:

g = 10

Step-by-step explanation:

Distribute 7 to the parentheses:

7(g + 5) = 105

7g + 35 = 105

Solve for g:

7g + 35 = 105

7g = 170

g = 10

So, the answer is g = 10

3 0
3 years ago
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If angle 1 = angle 2 and angle 2 = angle 4, what property allows you to state that angle 1 = angle 4
Gnesinka [82]

Answer:

Transitive Property

Step-by-step explanation:

You can use it for example: a = b. b = c. So a = c (Transitive Property).

6 0
3 years ago
What is 3/10 and 1/5 by using common
astra-53 [7]

Answer:

10

Step-by-step explanation:

5*2=10

10*1=10

so 1/5=2/10

3 0
3 years ago
Calculate the potential energy associated with 1 m^3 of water at 607 feet tall taking the mass of 1 m^3 of water to be 1000 kg
Lady bird [3.3K]

Answer:

1813.137 KJ

Step-by-step explanation:

potential energy of the body = mgH

where m is mass in Kg , g= 9.81 m/sec^2 and H= height in m

here m= 1000 kg, g= 9.81 m/s^2  and H= 607 feet = 607×0.305= 185.135 m

hence the potential energy p= 1000×9.81×185.135= 1813137.2 J

= 1813.137 KJ

hence the potential energy associated with 1 m^3 of water at 607 feet tall taking the mass as 1000 kg is = 1813.137 KJ

4 0
3 years ago
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