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blondinia [14]
3 years ago
15

The straight line P has the equation y= 2x-5

Mathematics
1 answer:
Sunny_sXe [5.5K]3 years ago
4 0

Answer:

y=−x/2+2.

Step-by-step explanation:

The equation of the line in the slope-intercept form is y=2x−5.

The slope of the perpendicular line is negative inverse: m=−12.

So, the equation of the perpendicular line is y=−x/2+a.

To find a, we use the fact that the line should pass through the given point: 3=(−12)⋅(−2)+a.

Thus, a=2.

Therefore, the equation of the line is y=−x/2+2.

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Which of the following terms are considered like terms? Select all that apply. (more than one)
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Step-by-step explanation:

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3 years ago
W/4 = -11 <br> please help !!!
Elis [28]
-44 because if u multiply -11 by 4 you get -44 and when divided by 4 you get -11
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WILL MARK BRAINLIST!!! A scale drawing of a living room is shown below. The scale is 1 : 40. A rectangle is shown. The length of
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3 years ago
Read 2 more answers
How to find minimum and maximum of this equation.
Westkost [7]

Using it's vertex, the maximum value of the quadratic function is -3.19.

<h3>What is the vertex of a quadratic equation?</h3>

A quadratic equation is modeled by:

y = ax^2 + bx + c

The vertex is given by:

(x_v, y_v)

In which:

  • x_v = -\frac{b}{2a}
  • y_v = -\frac{b^2 - 4ac}{4a}

Considering the coefficient a, we have that:

  • If a < 0, the vertex is a maximum point.
  • If a > 0, the vertex is a minimum point.

In this problem, the equation is:

y + 4 = -x² + 1.8x

In standard format:

y = -x² + 1.8x - 4.

The coefficients are a = -1 < 0, b = 1.8, c = -4, hence the maximum value is:

y_v = -\frac{1.8^2 - 4(-1)(-4)}{4(-1)} = -3.19

More can be learned about the vertex of a quadratic function at brainly.com/question/24737967

#SPJ1

3 0
2 years ago
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