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deff fn [24]
2 years ago
7

Find the value of b needed to make the

Mathematics
2 answers:
harina [27]2 years ago
4 0

Answer:

b = 64

Step-by-step explanation:

+(6 - 32) +b = 38       Distribute the "+" to (6 - 32)

6 - 32 + b = 38          Subtract

-26 + b = 38

+26        +26              Add 26 to both sides

b = 64

If this answer is correct, please make me Brainliest!

Ainat [17]2 years ago
3 0

Answer:

b = 64

Step-by-step explanation:

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2 years ago
Step by step explanation
SSSSS [86.1K]

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only a is the right triangle

Step-by-step explanation:

only a is the right triangle because it satisfies the pythagorean theorem.

a.)

c ^{2}  = a ^{2}  + b ^{2}  \\ 63 = 25 + 38\\ 63 = 63 \\ true

while b,

b.)

c ^{2}  = a ^{2}  + b ^{2}  \\ 60 = 25 + 38 \\ 60 = 63 \\ false

8 0
2 years ago
Can someone help me with this question? Thank you!
Harrizon [31]

\qquad\qquad\huge\underline{{\sf Answer}}

Let's evaluate ~

The given expression is :

\qquad \sf  \dashrightarrow \:4x + 8

plug the value of x as 3

\qquad \sf  \dashrightarrow \:4(3) + 8

\qquad \sf  \dashrightarrow \:12 + 8

\qquad \sf  \dashrightarrow \:20

Therefore, the required value is 20

8 0
1 year ago
The graph of a linear function passes through the points (2, 4) and (8, 10).
Keith_Richards [23]
\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%   (a,b)
&({{ 2}}\quad ,&{{ 4}})\quad 
%   (c,d)
&({{ 8}}\quad ,&{{ 10}})
\end{array}
\\\\\\
% slope  = m
slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{10-4}{8-2}

\bf \stackrel{\textit{point-slope form}}{y-{{ y_1}}={{ m}}(x-{{ x_1}})}\qquad 
\begin{array}{llll}
\textit{plug in the values for }
\begin{cases}
y_1=4\\
x_1=2\\
m=\boxed{?}
\end{cases}\\
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8 0
3 years ago
Enter the simplified form of the complex fraction in the box. Assume no denominator equals zero.
Olenka [21]

Answer:

\frac{(9-x)}{3x}

Step-by-step explanation:

we have

\frac{\frac{2}{x-3}-\frac{3}{x}}{\frac{3}{x-3}}

step 1

Solve the numerator of the quotient

\frac{2}{x-3}-\frac{3}{x}=\frac{2x-3(x-3)}{(x-3)x}=\frac{2x-3x+9}{(x-3)x}=\frac{9-x}{(x-3)x}

step 2

substitute in the original expression

\frac{\frac{9-x}{(x-3)x}}{\frac{3}{x-3}}

\frac{(x-3)(9-x)}{3x(x-3)}

step 3

simplify

\frac{(9-x)}{3x}

5 0
2 years ago
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