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Sunny_sXe [5.5K]
3 years ago
7

It takes 12 cups of chicken broth to make soup.how much is this in quarts?

Mathematics
1 answer:
DanielleElmas [232]3 years ago
4 0

1 quart = 4 cups

12/4 = 3

3 quarts total

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Reference angle for -19pi/6? 
kow [346]
\bf \cfrac{19}{6}\implies 3+\cfrac{1}{6}
\\ \quad \\\\
\cfrac{-19\pi }{6}\implies -\left(3\pi +\cfrac{1\pi }{6}  \right)\impliedby clockwise
\\ \quad \\\\
or\implies -\left(2\pi +\pi +\cfrac{\pi }{6}  \right)

go that much "clockwise", you'll end up at the 2nd quadrant,
the reference angle, is its reflective angle on the 1st quadrant

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The dimensions of a solid block of cheese in the shape of a triangular prism are shownbelow.6.9 cm9.9 cm5.1 cm. Which of the fol
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175 cm

Step-by-step explanation:

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(18+6)+(16+5)x5 <br><br><br>help?​
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Step-by-step explanation:

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You want to rent an unfurnished one-bedroom apartment in Boston next year. The mean monthly rent for a random sample of 10 apart
Brilliant_brown [7]

Answer:

90% confidence interval: (2186.53;2881.47)

95% confidence interval: (2118.73;2949.27)

99% confidence interval: (1987.37;3080.63)

For the last part is not the best way say : "This interval describes the price of 95% of the rents of all the unfurnished one-bedroom apartments in the Boston area."

The best interpretation is this one: "We are 95% confident that the actual mean for the rents of unfurnished one-bedroom apartments in the Boston area is between (2118.73;2949.27)"

Step-by-step explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=2534 represent the sample mean  

\mu population mean (variable of interest)

\sigma=670 represent the population standard deviation

n=10 represent the sample size  

90% confidence interval

The confidence interval for the mean is given by the following formula:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

Since the Confidence is 0.90 or 90%, the value of \alpha=0.1 and \alpha/2 =0.05, and we can use excel, a calculator or a tabel to find the critical value. The excel command would be: "=-NORM.INV(0.05,0,1)".And we see that z_{\alpha/2}=1.64

Now we have everything in order to replace into formula (1):

2534-1.64\frac{670}{\sqrt{10}}=2186.53    

2534+1.64\frac{670}{\sqrt{10}}=2881.47

So on this case the 90% confidence interval would be given by (2186.53;2881.47)

95% confidence interval

The confidence interval for the mean is given by the following formula:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a tabel to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that z_{\alpha/2}=1.96

Now we have everything in order to replace into formula (1):

2534-1.96\frac{670}{\sqrt{10}}=2118.73    

2534+1.96\frac{670}{\sqrt{10}}=2949.27

So on this case the 95% confidence interval would be given by (2118.73;2949.27)

99% confidence interval

The confidence interval for the mean is given by the following formula:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

Since the Confidence is 0.99 or 99%, the value of \alpha=0.01 and \alpha/2 =0.005, and we can use excel, a calculator or a tabel to find the critical value. The excel command would be: "=-NORM.INV(0.005,0,1)".And we see that z_{\alpha/2}=2.58

Now we have everything in order to replace into formula (1):

2534-2.58\frac{670}{\sqrt{10}}=1987.37    

2534+2.58\frac{670}{\sqrt{10}}=3080.63

So on this case the 99% confidence interval would be given by (1987.37;3080.63)

For the last part is not the best way say : "This interval describes the price of 95% of the rents of all the unfurnished one-bedroom apartments in the Boston area."

The best interpretation is this one: "We are 95% confident that the actual mean for the rents of unfurnished one-bedroom apartments in the Boston area is between (2118.73;2949.27)"

7 0
3 years ago
ANSWER ASAP PLEASE BEST ANSWER HETS BRAILIEST!!!
puteri [66]
The answer is A, because y shows the values for x
4 0
3 years ago
Read 2 more answers
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