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2 years ago

Find the arclength along a circle of diameter 3.9 3.9 meters which subtends an angle of 6.7 6.7 radians.

1 answer:

6 0

Arc length = r θ =(3.9/2)*6.7 = 13.065 m.
Note: This arc angle is over 2 π , meaning that it will more than wrap around the circle.

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What are real-world examples of translation, reflection, rotation, and dilation\stretch.

bonufazy [111]

Answer:

Translation: Moving an apple from one area to another area.

Reflection: Mirrors.

Rotation: Rotating a car wheel.

Step-by-step explanation:

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3 years ago

Solve equation by using the quadratic formula.

adoni [48]

ANSWER IS C because I looked it up

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2 years ago

Emilio has to run 7 1/2 miles a week to train for the football team. If he runs 1 1/2 miles everyday , how many days will it tak

PilotLPTM [1.2K]

Answer:

5 days

Step-by-step explanation:

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3 years ago

Read 2 more answers

The 1992 world speed record for a bicycle (human-powered vehicle) was set by Chris Huber. His time through the measured 200 m st

Reil [10]

Answer:

a) 30.726m/s and b) 5.5549s

Step-by-step explanation:

a.) What was Chris Huber’s speed in meters per second(m/s)?

Given the distance and time, the formula to obtain the speed is

$v=\frac{d}{t}$ .

Applying this to our problem we have that

$v=\frac{200m}{6.509s}= 30.726m/s$ .

So, Chris Huber’s speed in meters per second(m/s) was 30.726m/s.

b) What was Whittingham’s time through the 200 m?

In a) we stated that $v=\frac{d}{t}$ . This formula implies that

$t=\frac{d}{v}$ .

First, observer that $19\frac{km}{h} =19,000\frac{m}{h}=\frac{19,000}{3,600}m/s= 5.2777m/s$ .

Then, Sam Whittingham speed was equal to Chris Huber’s speed plus 5.2777 m/s. So, $v=30.726\frac{m}{s} +5.2777\frac{m}{s}= 36.003 m/s.$

Then, applying 1) we have that

$t=\frac{200m}{36.003m/s}=5.5549s.$

So, Sam Whittingham’s time through the 200 m was 5.5549s.

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3 years ago

Given h(x) = 4x−4, find h(−3)

Hunter-Best [27]

Answer:

-16

Step-by-step explanation:

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2 years ago