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3 years ago

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Find the volume of the hollow prism as shown (in cubic ft.)

1 answer:

azamat3 years ago

6 0

I hope this helps you

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Help me please. I don’t understand this math. My math teacher is mean. :(((((

Verdich [7]

Answer:

The height of the given rectangular prism is 5cm.

Step-by-step explanation:

Given that the volume of the rectangular prism is $5cm^3$

And length is $\frac{3}{4}$ and width is $1\frac{1}{3}$

That is V=5cm^3[/tex] , $l=\frac{3}{4}cm$ and $w=1\frac{1}{3}cm$

We have the volume of the rectangular prism V=lwh cubic centimeter

$V=lwhcm^3$

Substituting the values in above formula

$5=\frac{3}{4}\times 1\frac{1}{3}\times h$

$5=\frac{3}{4}\times \frac{4}{3}\times h$

$5=1\times h$

$5=h$

Rewritting as below

$h=5cm$

Therefore the height is 5cm

5 0

3 years ago

Read 2 more answers

What is the length of each piece????PLEASE HELP!!!!

Alex787 [66]

The last one because its a side length if 26 inches so you spit in half

3 0

3 years ago

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2 tan 30°<br>II<br>1 + tan- 300

shusha [124]

Question:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$

Answer:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= sin(60^{\circ})$

Step-by-step explanation:

Given

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$

Required

Simplify

In trigonometry:

$tan(30^{\circ}) = \frac{1}{\sqrt{3}}$

So, the expression becomes:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2 * \frac{1}{\sqrt{3}}}{1 + (\frac{1}{\sqrt{3}})^2}$

Simplify the denominator

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2 * \frac{1}{\sqrt{3}}}{1 + \frac{1}{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\frac{2}{\sqrt{3}}}{1 + \frac{1}{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\frac{2}{\sqrt{3}}}{ \frac{3+1}{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\frac{2}{\sqrt{3}}}{ \frac{4}{3}}$

Express the fraction as:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2}{\sqrt 3} / \frac{4}{3}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2}{\sqrt 3} * \frac{3}{4}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{1}{\sqrt 3} * \frac{3}{2}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{3}{2\sqrt 3}$

Rationalize

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{3}{2\sqrt 3} * \frac{\sqrt{3}}{\sqrt{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{3\sqrt{3}}{2* 3}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\sqrt{3}}{2}$

In trigonometry:

$sin(60^{\circ}) = \frac{\sqrt{3}}{2}$

Hence:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= sin(60^{\circ})$

3 0

3 years ago

Consider a function that describes how a particular car’s gas mileage depends on its speed. What would be an appropriate domain

natta225 [31]

Domain are x values (independent variable);

Speed would be independent so what speeds can be used ? -30 mph, 30 mph, 1000 mph?

Can a car go 0 mph?

What is realistic?

I would say 0 greater or equal to x greater than whatever you think is beyond the max that a car can go.

8 0

3 years ago

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0.679 what is the value of the number 6 digit

TiliK225 [7]

Answer:

6 tenths or 0.6, I hope this is what you mean.

Step-by-step explanation:

8 0

3 years ago