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miskamm [114]
3 years ago
7

Perform the indicated operation ?

Mathematics
2 answers:
Setler [38]3 years ago
7 0

Answer: g(n)\cdot h(n)=2n^4+4n^3-4n^2-8n

Step-by-step explanation:

The given functions :

g(n)=n^3-2n\\\\ h(n)=2n+4 of same variable n.

The indicated operation here is multiplication.

Therefore,

g(n)\cdot h(n)=(n^3-2n)(2n+4)\\\\n^3(2n)+n^3(4)-2n(2n)-2n(4)\\\\=2n^4+4n^3-4n^2-8n

Hence, g(n)\cdot h(n)=2n^4+4n^3-4n^2-8n

pav-90 [236]3 years ago
6 0
2n^4+4n^3-4n^2-8n
Replace g(n) and h(n) with the functions to multiply
(n^{3} -2n)*(2n+4)
Multiply the First, Inner, Outer, and Last terms in the parentheses. when multiplying a variable the exponents of the same base add together.
(n^{3} -2n)*(2n+4) = 2n^4+4n^3-4n^2-8n

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2 years ago
The length of a rectangle is six times it’s width. If the area of the rectangle is 150ft^2, find its perimeter.
sineoko [7]

Answer:

Perimeter = 70ft

Step-by-step explanation:

Area of a rectangle is:

area = (length * width)

150 = a * b

a = 6b

a = length

b = width

then:

150 = 6b*b

150 = 6b²

b² = 150/6

b² = 25

√b² = √25

b = 5ft

a = 6b

a = 6*5

a = 30ft

then:

perimeter of a rectangle is:

p = 2(a+b)

p = 2(30 + 5)

p = 2*35

p = 70ft

7 0
3 years ago
In the figure, m and n are rays.
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4 0
4 years ago
Help ASAP!!!<br><br> Identify the correct trigonometry formula to use to solve for x.
Alex787 [66]

Answer:

cos(55) = 11/x

Step-by-step explanation:

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4 0
3 years ago
Read 2 more answers
6. If you draw 35 lines on a piece of paper so that no two lines are parallel to each
umka2103 [35]

The point of intersection is the point where lines intersect.

<em>There will be 595 intersections for 35 lines, where no 3 lines are concurrent.</em>

<em />

Given

<em />n = 35<em> --- the number of lines</em>

<em />d = 3<em> --- no three lines are concurrent</em>

<em />

When no three line are concurrent, it means that no three lines meet at the same point.

<u>So, the sequence of intersection is:</u>

  • <em>0 intersection for 1 line</em>
  • <em>1 intersection for 2 lines</em>
  • <em>3 intersections for 3 lines</em>
  • <em>6 intersections for 4 lines</em>

<em />

Following the above sequence, the number of intersections for n lines is:

n_k = \frac{n \times (n - 1)}{2}

In this case, n = 35.

So, we have:

n_k = \frac{35 \times (35 - 1)}{2}

n_k = \frac{35 \times 34}{2}

n_k = 35 \times 17

n_k = 595

<em>Hence, there will be 595 intersections for 35 lines, where no 3 lines are concurrent.</em>

<em />

Read more about lines of intersections at:

brainly.com/question/22368617

7 0
3 years ago
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