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Paha777 [63]
3 years ago
5

300 school children went on a field trip. 30% of them were first graders, 45% second graders and the rest were third graders. Ho

w many more first graders were there than third graders
Mathematics
1 answer:
mrs_skeptik [129]3 years ago
3 0

Answer:

just take 45 and 30 percent add them to get 75% so find 75 percent of 300 then subtract it and you get 75

Step-by-step explanation:

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what is the smallest positive integer a such that the intermediate value theorem guarantees a zero exists between 0 and a?
liberstina [14]

The smallest positive integer that the intermediate value theorem guarantees a zero exists between 0 and a is 3.

What is the intermediate value theorem?

Intermediate value theorem is theorem about all possible y-value in between two known y-value.

x-intercepts

-x^2 + x + 2 = 0

x^2 - x - 2 = 0

(x + 1)(x - 2) = 0

x = -1, x = 2

y intercepts

f(0) = -x^2 + x + 2

f(0) = -0^2 + 0 + 2

f(0) = 2

(Graph attached)

From the graph we know the smallest positive integer value that the intermediate value theorem guarantees a zero exists between 0 and a is 3

For proof, the zero exists when x = 2 and f(3) = -4 < 0 and f(0) = 2 > 0.

<em>Your question is not complete, but most probably your full questions was</em>

<em>Given the polynomial f(x)=− x 2 +x+2 , what is the smallest positive integer a such that the Intermediate Value Theorem guarantees a zero exists between 0 and a ?</em>

Thus, the smallest positive integer that the intermediate value theorem guarantees a zero exists between 0 and a is 3.

Learn more about intermediate value theorem here:

brainly.com/question/28048895

#SPJ4

4 0
2 years ago
An arithmetic sequence starts<br> -10, -13, -16,<br> Find the sum of its first 35 terms.
34kurt

Answer:

-10,-13,-16 and importance of being in a good night friends ni pta nhi hai to you

4 0
2 years ago
Solve cos x + rad 2 = -cos x for over the interval [0, 2pi ]
Kamila [148]
cos x + \sqrt{2} = -cosx \\  \\ 2 cos x + \sqrt{2} = 0 \\  \\ cos x = -\frac{\sqrt{2}}{2}

The cosine function is negative in 2nd and 3rd quadrants, So you know that you will have 2 solutions. One between pi/2 and pi, the other between pi and 3pi/2.

Refer to a unit circle to find that 
cos (\frac{3\pi}{4}) = -\frac{\sqrt{2}}{2}  \\  \\ cos (\frac{5\pi}{4}) = -\frac{\sqrt{2}}{2}

Final Answer:
x = \frac{3\pi}{4}, \frac{5\pi}{4}
6 0
3 years ago
The following dot plots describe the test scores on Mr. Santos final exam.
Tasya [4]

second-period class average:

55+70+450+480+170+270+95 = 1590

1590/20 = 79.5

sixth-period class average:

65+225+480+595+270+190 = 1825

1825/20 = 91.25

on average, students in the sixth period class scored higher

5 0
3 years ago
What are the measures of the angles in triangle ABC?
VMariaS [17]

Complete question :

A right triangle has side lengths AC = 7 inches, BC = 24 inches, and AB = 25 inches.

What are the measures of the angles in triangle ABC?

a) m∠A ≈ 46.2°, m∠B ≈ 43.8°, m∠C ≈ 90°

b) m∠A ≈ 73.0°, m∠B ≈ 17.0°, m∠C ≈ 90°

c) m∠A ≈ 73.7°, m∠B ≈ 16.3°, m∠C ≈ 90°

d) m∠A ≈ 74.4°, m∠B ≈ 15.6°, m∠C ≈ 90°

Answer:

c) m∠A ≈ 73.7°, m∠B ≈ 16.3°, m∠C ≈ 90°

Step-by-step explanation:

Given:

Length AC = 7 inches

Length BC = 24 inches

Length AB = 25 inches

Since it is a right angle triangle,

m∠C = 90°

To find the measures of the angle in ∠A and ∠B, we have :

For ∠A:

SinA = \frac{BC}{AB}

SinA = \frac{24}{25}

SinA = 0.96

A = Sin^-^1 = 0.96

∠A = 73.7°

For ∠B:

SinB = \frac{AC}{AB}

SinB = \frac{7}{25}

SinB = 0.28

B = Sin^-^1 = 0.96

∠B = 16.26 ≈ 16.3°

Therefore,

m∠A = 73.7°

m∠B = 16.3°

m∠C = 90°

7 0
3 years ago
Read 2 more answers
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