$ax^2+bx+c=0\\\\the\ vertex:\left(\frac{-b}{2a};\frac{-(b^2-4ac)}{4a}\right)\\\\y-intrcept=c\\=======================================\\\\4x^2-5x-15=0\\\\a=4;\ b=-5;\ c=-15\\\\\frac{-b}{2a}=\frac{-(-5)}{2\cdot4}=\frac{5}{8};\ \frac{-(b^2-4ac)}{4a}=\frac{-[(-5)^2-4\cdot4\cdot(-15)]}{4\cdot4}=-\frac{265}{16}\\\\\boxed{the\ vertex:\left(\frac{5}{8};-\frac{265}{16}\right)}\\\\\boxed{y-intercept:-15}$

5 0

3 years ago

Please please help me on this

Goryan [66]

Answer:

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Help me plzzzzzzz guyssss

maks197457 [2]

Answer:

1. 75%

2. 20%

3. 20%

4. decrease 5.4%

Step-by-step explanation:

1. 119-68=51, 51/68=0.75

2. 30-24=6, 6/30=0.20

3. 18-15=3, 3/15=0.20

4. 762-721=41, 41/762=0.0538

5 0

2 years ago