Yiu need to first off start withe the first number and then get the answer
Answer:
a^(-2/3)
Step-by-step explanation:
(a^2/3)^-1
We know x^y^z = x^(y*z)
a^(2/3*-1)
a^(-2/3)
To simplify 3a + 2b - 8a + b, we need to combine like terms. Like terms are terms that share common variables. In this expression, the two variables are terms with a and terms with b. The terms that have a are 3a and -8a. The terms that have b are 2b and b. Now we can separate them and simplify.
(3a - 8a) + (2b + b)
-5a + 3b
Answer:
169 
Step-by-step explanation:
Ok so we know that perimeter is when you add up all the side lengths of a given shape. Since we know it's 52, we can use that to help us!
A square means that all 4 sides are equal; all 4 side lengths are equal...
Now we can divide the perimeter by 4 (a square has 4 sides) to get the side lengths for one side of the square (when we get one side, we automatically have the other sides)
52 ÷ 4 = 13
The side lengths for the square is 13
Check...
13 + 13 + 13 + 13 = 52 CORRECT
Now that we have the side of the square, we can find the area...
A = b * h
A = 13 * 13
A = 169
The area of the square is 169
Hope this helped!
Have a supercalifragilisticexpialidocious day!
<h3>
ANSWERS:</h3>
1. Line XY
2. Line XZ
3. (opposite angle): IU
(adjacent angle): IH
Question 1:
For the first problem, you are finding the opposite side to ∠YZX, by knowing that Z is the center of this angle, it is rather simple to solve.
Just draw your line through the middle of the angle through the triangle until you hit the side on the other side.
When doing this on question 1, you would pass between the angles of ∠X and ∠Y, <u><em>therefore you are passing through line XY.</em></u>
Question 2:
For the next problem, we need the adjacent angle to ∠YZX, in other words the one other line which is not the opposite angle.
By doing that we can rule it down to lines XZ and YZ, but it cannot be angle YZ because that is the hypotenuse of the triangle (the longest side) and cannot ever be the opposite or adjacent lines.
<u><em>So, your answer for question 2 would be line XZ.</em></u>
Question 3:
For the last problem, we need to find both the opposite and adjacent sides of the triangle according to angle ∠IHU.
So, firstly, do that finger through the center of the angle trick for the opposite angle and you would get line IU.
Then for the adjacent angle, find the hypotenuse and choose the one other angle that you haven't chosen as your opposite angle.
By doing that, you would get line IH.
