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Ahat [919]
3 years ago
10

Two angles are adjacent and form an angle of 160. Their difference is 34. Find the angles​

Mathematics
1 answer:
Sholpan [36]3 years ago
6 0

Answer:

The angles are 63 , 97

Step-by-step explanation:

Let one angle be x

As sum of two angles is 160, the other angle = 160 - x

Their difference  = 34

x - [160- x] = 34

Use distributive property to remove the brackets

x - 160 + x = 34

Add like terms

x + x - 160 = 34

2x - 160 = 34

Add 160 to both sides

2x  = 34 + 160

2x = 194

Divide both sides by 2

2x/2 = 194/2

x = 97°

One angle = 97°

Other angle = 160 - 97 = 63°

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dimaraw [331]

The value of t  at a height of 11 feet is 0.36 sec when the ball is going upwards and 1.39 seconds when the ball is coming downwards.

<h3>What is a quadratic equation?</h3>

A quadratic equation is an equation whose leading coefficient is of second degree also the equation has only one unknown while it has 3 unknown numbers.

It is written in the form of ax²+bx+c.

Given that the height of the ball at time t is given by the function,

h(t) = 3+ 28t -16t^2

where t is in seconds and h is in feet.

Now, the height of the ball is given to be 11 feet, therefore, substituting the value of h in the function as 11,

h(t) = 3+ 28t -16t^2\\\\11 = 3+ 28t -16t^2\\\\-16t^2 + 28t +3 -11 = 0\\\\-16t^2 + 28t -8 = 0

Now, solving the given quadratic equation, we will get,

x= \dfrac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\t = \dfrac{-(28)\pm \sqrt{(28)^2-4(-16)(-8)}}{2(-16)}\\\\t= 0.36\ or\ 1.39

Hence, the value of t  at a height of 11 feet is 0.36 sec when the ball is going upwards and 1.39 seconds when the ball is coming downwards.

Learn more about Quadratic Equations:

brainly.com/question/2263981

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Answer:

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Step-by-step explanation:

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100%=150

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to check find 90% of 150 which is 135

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