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harkovskaia [24]
3 years ago
5

Solve the following equation. c/4 = 12​

Mathematics
1 answer:
nexus9112 [7]3 years ago
4 0

Answer:

48

Step-by-step explanation:

c÷4=12

4×c÷4=4×12

c=48

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What is the negative x-intercept of the graph of the quadratic function f(x) = 5x2 + 4x - 1?
iragen [17]
The answer should be y = 5x^2+4x-1

8 0
3 years ago
Which expressions are equivalent to (5⋅x)⋅3 ? Drag and drop the equivalent expressions into the box.
marysya [2.9K]
<h2>Greetings!</h2>

Answer:

3⋅(5⋅x)

5⋅(x⋅3)

15x

Step-by-step explanation:

As the values are inside the brackets, it does not matter what side the (x3) is on, so 3⋅(5⋅x) is equivalent.


Multiplying the contents of the brackets in the third one (x * 3) by 5 gives the same value as 3 * (x * 5) so 5⋅(x⋅3) is also equivalent.


On multiplying the brackets out:

5 * x = 5x

5x * 3 = 15x

So 15x is also equivalent.


<h2>Hope this helps!</h2>
3 0
3 years ago
The sides of a triangle are in the ratio 5 : 12 : 13. What is the length of each side of the triangle if the perimeter of the tr
Ganezh [65]

Answer:

2.5, 6 and 6.5 inches.

Step-by-step explanation:

5 + 12 + 13 = 30

So the shortest side = 5/30 * 15 = 1/6 * 15

= 2.5 inches.

The longest = 13 / 30 * 15 =  13/2

= 6.5 inches,

and the third = 12/30 * 15

= 6 inches.

4 0
2 years ago
A ball is thrown in the air from a height of 3 m with an initial velocity of 12 m/s. To the nearest tenth of a second, how long
stepladder [879]

Answer:  1.4 seconds

<u>Step-by-step explanation:</u>

The equation is: h(t) = at² + v₀t + h₀          where

  • a is the acceleration (in this case it is gravity)
  • v₀ is the initial velocity
  • h₀ is the initial height

Given:  

  • a = -9.81 (if it wasn't given in your textbook, you can look it up)
  • v₀ = 12
  • h₀ = 3

Since we are trying to find out when it lands on the ground, h(t) = 0

EQUATION:   0 = 9.81t² + 12t + 3

Use the quadratic equation to find the x-intercepts

                        a=-9.81, b=12, c=3

x=\dfrac{-b \pm \sqrt{b^2-4ac}}{2a}\\\\\\x=\dfrac{-(12)\pm \sqrt{(12)^2-4(-9.81)(3)}}{2(-9.81)}\\\\\\x=\dfrac{-12\pm 16.2}{-19.62}\\\\\\x=\dfrac{-12+ 16.2}{-19.62}=-0.2\qquad x=\dfrac{-12- 16.2}{-19.62}=\large\boxed{1.4}\\

Note: Negative time (-0.2) is not valid

4 0
3 years ago
What is the equation of this line?<br> Please Help <br><br> Y=4x<br> Y=-1/4x<br> Y=-4x<br> Y=1/4x
Sveta_85 [38]

Answer: Y=-1/4x

Step-by-step explanation:

A good way to find an equation of a line is to look for the slope. An obvious spot on this line would be when it crosses (0,0), and another one to the right would be when it crosses at (4,-1).

The slope is rise over run, or if we use the two points we found, "rise" would be -1, because it's dropping 1 unit when going from (0,0) to (4,-1), and the "run" would be 4, because it moves to the right 4 from (0,0) to (4,-1).

Putting these two values together we get:

m (slope) = rise / run

m = -1 / 4

Out of all the equations we're given, we can look for the one with a slope of -1/4, which is given to us:

y = (-1/4)x

7 0
3 years ago
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