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Fittoniya [83]
3 years ago
7

Factor: 2a^2-ab-6b^2

Mathematics
1 answer:
pogonyaev3 years ago
5 0

Rewrite the expression as

2a^2-4ab+3ab-6b^2

Factor 2a from the first two terms and 3b from the last two:

2a(a-2b)+3b(a-2b)

Factor a-2b

(a-2b)(2a+3b)

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There are the two photos to solve it and jus write A B or C please
Sidana [21]
The answer would be B
8 0
3 years ago
An arhitect wants to draw a rectangle with a diagonal of 20 inches. The length of the rectangle is to be 8 inches more than twic
kiruha [24]

The diagonal of a rectangle = sqrt(w^2 + l^2)

w = width

l = length

In this problem,

The diagonal = 20 in

w = x

l = 2x + 8

Let's plug our numbers into the formula above.

20in = sqrt((x)^2 + (2x + 8)^2)

Let's simplify the inside of the sqrt

20 in = sqrt(5x^2 + 32x + 64)

Now, let's square both sides.

400 = 5x^2 + 32x + 64

Subtract 400 from both sides.

0 = 5x^2 + 32x - 336

Factor

0 = (5x - 28)(x + 12)

Set both terms equal to zero and solve.

x + 12 = 0

Subtract 12 from both sides.

x = -12

5x - 28 = 0

Add 28 to both sides.

5x = 28

Divide both sides by 5

x = 28/5

The width cant be a negative number so now we know that the only real solution is 28/5

Let's plug 28/5 into our length equation.

Length = 2(28/5) + 8 = 56/5 + 8 = 96/5

In conclusion,

Length = 96/5 inches

Width = 28/5

4 0
2 years ago
Kyra multiplied 0.27 by a power of ten and got 2.7. What power of ten did she multiply by?
sveticcg [70]

Answer:

the answer would be A.

Step-by-step explanation:

Look for how many decimal places the decimal moved and thats how many 0's would be in your number

7 0
3 years ago
Come hither big brains
katrin2010 [14]

Answer:

The answer is c

Step-by-step explanation:

7 0
2 years ago
Given cos theta=4/9 and csc theta 0 find sin theta and tan theta
Korvikt [17]
The correct question is
<span>Given cos theta=4/9 and csc theta < 0 find sin theta and tan theta
</span>
we know that
csc theta=1/sin theta
if csc theta < 0
then 
sin theta < 0

we have that
<span>cos theta=4/9

we know that
sin</span>² theta+cos² theta=1
so
sin² theta=1-cos² theta-----> 1-(4/9)²----> 1-(16/81)----> 65/81
sin theta=-√(65/81)---->-√65/9

the answer Part a) is 
sin theta=-√65/9

Part b) find tan theta

tan theta=sin theta/cos theta
tan theta=(-√65/9)/(4/9)-----> tan theta=-√65/4

the answer part b) is
tan theta=-√65/4
5 0
3 years ago
Read 2 more answers
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