Finding side of right triangle when you know the hypotenuse and one side

Determine if the given lines are parallel, perpendicular or neither. 2x + 7y = 4 y = 3x + 5

bixtya [17]

Answer:

Perpendicular

Step-by-step explanation:

6 0

4 years ago

Solve for y in the following equation.

Tju [1.3M]

Answer:

$y = \frac{z^2 - x}{2}$

Step-by-step explanation:

Given:

$\sqrt{x + 2y} = z$

Required:

Solve for y (make y the subject of the formula)

SOLUTION:

$\sqrt{x + 2y} = z$

Square both sides

$(\sqrt{x + 2y})^2 = z^2$

$x + 2y = z^2$

Subtract both sides by x

$2y = z^2 - x$

Divide both sides by 2

$y = \frac{z^2 - x}{2}$

5 0

3 years ago

Q4 Help pleaseeeeeeee

emmasim [6.3K]

a. The general equation for a circle centered at $(a,b)$ with radius $r$ is

$(x-a)^2+(y-b)^2=r^2$

The described circle has equation

$(x+3)^2+(y+2)^2=r^2$

We know the circle passes through the origin. This means that the equation above holds for $x=0$ and $y=0$ . The distance between any point on the circle and its center is the radius, so we can use this fact to determine $r$ :

$(0+3)^2+(0+2)^2=r^2\implies 9+4=13=r^2\implies r=\sqrt{13}$

So the circle's equation is

$(x+3)^2+(y+2)^2=(\sqrt{13})^2=13$

b. If the distance between point B and the center is less than $\sqrt{13}$ , then B lies inside the circle. If the distance is greater than $\sqrt{13}$ , it falls outside the circle. Otherwise, if the distance is exactly $\sqrt{13}$ , then B lies on the circle.

The distance from B to the center is

$\sqrt{(-1+3)^2+(3+2)^2}=\sqrt{4+25}=\sqrt{29}$

$29>13$ , so $\sqrt{29}>\sqrt{13}$ , which means B falls outside the circle.

5 0

3 years ago

How to find the area of the shaded areas and to round the nearest hundredth please and thank you it help me a lot if you could a

andrew-mc [135]

<h3>Please Read Through This, Answers are Listed.</h3>

As a heads up, this post is going to be very long.

So to do these questions, first know what you need to do.

Goals to do:

1 - Find the area of the circle

2 -Find how much of it is shaded

3 -Find the shaded's area.

So, the first goal is to find the area of the circle, well that's fairly simple. Just do pi r². (r stands for the radius)

With the first question, they list the length GH as 11 inches. So just plug it in!

pi 11² ---> pi * 121 ---> ≈380.13

Next, find the amount that is shaded. So with that, look at the angle inside the circle, it is 64°. By knowing that the whole circle is 360°, just do 64/360 to find the an "important number".

64/360 ---> 0.17777777...

By using this important number and multiplying it with your total circle area, you'll get your answer.

380.13 * 0.17777777... ---> ≈ 67.6in² (QUESTION 1 ANSWER)

And then just do the same with the rest...

Question 2:

pi 22² ---> pi * 484 ---> 1520.53

139/360 ---> 0.38611

1520.53 * 0.38611 ---> ≈ 587.09cm² (QUESTION 2 ANSWER)

Question 3:

pi 3² ---> pi * 9 ---> 28.27

84/360 ---> 0.2333...

28.27 * 0.2333 ---> ≈6.60mm² (QUESTION 3 ANSWER)

Question 4:

pi 14.2² ---> pi * 201.64 ---> 633.47

***Because the angle is in the blank space, subtract it from 360 first before continuing.

360 - 87 ---> 273/360 ---> 0.7583333

633.47 * 0.7583333 ---> ≈480.38m² (QUESTION 4 ANSWER)

Question 5:

pi 9² ---> pi * 81 ---> 254.47

***Because the angle is in the blank space, subtract it from 360 first before continuing.

360 - 42 ---> 318/360 ---> 0.88333

254.47 * 0.88333 ---> ≈224.78in² (QUESTION 5 ANSWER)

Question 6:

pi 28² ---> pi * 784 ---> 2463.01

115/360 ---> 0.319444

2463.01 * 0.319444 ---> ≈786.79m² (QUESTION 6 ANSWER)

Question 7:

pi 32.5² ---> pi * 1056.25 ---> 3318.31

29/360 ---> 0.080555

3318.31 * 0.080555 ---> ≈267.31ft² (QUESTION 7 ANSWER)

Question 8

pi 29.5² ---> pi *870.25 ---> 2733.97

***Because the angle is in the blank space, subtract it from 360 first before continuing. Along with that, the angle has a square in place of a number, meaning that it is a right angle, or 90°.

360-60 ---> 270/360 ---> 0.75

2733.97 * 0.75 ---> 2050.48mi² (QUESTION 8 ANSWER)

8 0

4 years ago

I don't get math and will never get it can u help ?

Ksju [112]

Practice is key in mathematics! Always search up the topic and re-read the lessons with some practice problems to see if you got it. Asking your teacher and peers to help is another way to go.

Remember, your teacher had to learn this in order to teach you about it!

4 0

4 years ago