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2 years ago

PLEASE HELP ME ASAP?!?(2questions) 60POINTS+BRAINLIEST

1 answer:

4 0

It says that there was an error with my answer, but I don't know what, so I screenshotted what I typed and attached them as 4 images below:

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mr_godi [17]

3m-10=2(4m-5)
3m-10=8m-10
3m-8m=-10+10
-5m=0
m=0

4 0

3 years ago

NNADVOKAT [17]

I think the answer is B but I am not sure

7 0

3 years ago

Nat2105 [25]

Answer:

The midpoint of the given coordinates is $(\frac{23}{2},\frac{23}{2})\ or\ (11.5,11.5)$ .

Step-by-step explanation:

We have given two coordinates (3,15) and (20,8).

Let we have given a line segment PQ whose P coordinate is (3,15) and Q coordinate is (20,8).

We have to find out the mid point M(x,y) of the line segment PQ.

Solution,

By the mid point formula of coordinates, which is;

$(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})$

On substituting the given values, we get;

$M(x,y)=(\frac{3+20}{2}, \frac{15+8}{2})\\\\M(x,y)=(\frac{23}{2},\frac{23}{2})$

We can also say that $M(x,y)=(11.5,11.5)$

Hence The midpoint of the given coordinates is $(\frac{23}{2},\frac{23}{2})\ or\ (11.5,11.5)$ .

3 0

3 years ago

siniylev [52]

Make them both improper fractions
13/3 divided by 11/9
Divide = multiply reciprocal
13/3 * 9/11 = 117/11 = 10 7/11

4 0

2 years ago

Varvara68 [4.7K]

Answer:

The answer is B

Step-by-step explanation:

5 0

2 years ago