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agasfer [191]
3 years ago
10

I need help of question #36

Mathematics
1 answer:
Tju [1.3M]3 years ago
6 0
Check the picture below.

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Step-by-step explanation:

It’s c I think idk

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Answer:

I could do 1 and 3

1) 2x-3y=-2 ....1

-

2x+y=14......2

=-4y=-16

y=4

<u>Substitute</u><u> </u><u>(</u><u>y</u><u>=</u><u>4</u><u>)</u><u> </u><u>into</u><u> </u><u>equation</u><u> </u><u>1</u>

2x-3 (4)=-2

2x-12=-2

2x=-2+12

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×=5

3) 5x+5y=20....1

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-3x+5y=4......2

=8x=16

x=2

<u>S</u><u>ubstitute</u><u> </u><u>(</u><u>x</u><u>=</u><u>2</u><u>)</u><u> </u><u>into</u><u> </u><u>equation</u><u> </u><u>1</u>

<u>5</u><u> </u><u>(</u><u>2</u><u>)</u><u>+</u><u>5y</u><u>=</u><u>20</u>

<u>10</u><u>+</u><u>5y</u><u>=</u><u>20</u>

<u>5y</u><u>=</u><u>20-10</u>

<u>5y</u><u>=</u><u>10</u>

<u>y</u><u>=</u><u>2</u>

5 0
3 years ago
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<img src="https://tex.z-dn.net/?f=24x%5E%7B2%7D%2Bbx%5E%7B2%7D%20%3D25x%5E%7B2%7D" id="TexFormula1" title="24x^{2}+bx^{2} =25x^{
Liula [17]

Answer:

x = 0

Step-by-step explanation:

Subtract 25x^2 from both sides

24x^2 + bx^2 - 25x^2 - 25x^2

Simplify

bx^2 - x^2 = 0

Factor bx^2 - x^2: x^2(b - 1)

bx^2 - x^2

Factor out common term x^2

= x^2 (b - 1)

x^2(b - 1) = 0

Using the Zero Factor Principle: If ab = 0 then a = 0 or b = 0

x^2 = 0

Apply rule x^n = 0   x = 0

x = 0

8 0
3 years ago
Please help with question 11! BRAINLIEST to correct answer!!
Contact [7]

Answer:

No

Step-by-step explanation:

you can see that they can not go into each other and come out correct so the answer would have to be no (we were working on this same thing)

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