Answer:
15(2r^2+2r+5)
Step-by-step explanation:
I'm more of a guess and check type of person, but 15 x 2r^2 = 30r^2, 15 x 2r = 30r, and 15 x 5 = 75
Answer:
a 
b 
c 0 customers
Step-by-step explanation:
Given

per customer
Solving (a): Amount (A) on n customers
This is calculated as:



Solving (b): Amount on 134 customers
In this case: n = 134
So:



Solving (c): Customers at noon.
At noon, the amount is 30.
So:


Collect like terms



4x³ - 6x² + 10x - 15
2x²(2x) - 2x²(3) + 5(2x) - 5(3)
2x²(2x - 3) + 5(2x - 3)
(2x² + 5)(2x - 3)
The answer is B.
Step-by-step explanation:
Let's say R is the initial radius of the sphere, and r is the radius at time t.
The volume of the sphere at time t is:
V = 4/3 π r³
Taking derivative with respect to radius:
dV/dr = 4π r²
This is a maximum when r is a maximum, which is when r = R.
(dV/dr)max = 4π R²
This is 4 times the sphere's initial great circle area, but not the great circle circumference. The problem statement contains an error.