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QveST [7]
3 years ago
5

Clay went for a run to prepare for a long distance race comin up. From his house, he ran 6. Miles directly north and then 8 mile

s directly west. From there he ran the diagonal distance back to his house. How many total miles did clay run?
Mathematics
1 answer:
elena-s [515]3 years ago
7 0

Answer:

Clay ran 24 miles in total.

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Bob is mailing packages. Each small package costs him $3.40 to send. Each large package costs him $5.10. How much will it cost h
Tatiana [17]

Answer:

$28.9

I hope this help also I would appreciate brainliest if possible :)

8 0
3 years ago
a A hole in the shape of a hemisphere is carved into each face of a cube. The holes are identical and centered at the centre of
morpeh [17]

Diameter of each hemispheral holes = the diameter of a full sphere = side length of cube = 2 units.

<h3>What is a Hemisphere?</h3>

A hemishpere is half of a sphere. Thus, two hemispheres makes one full sphere.

Given the image as shown below, since the identical hemispheral holes are centered at the center of each fce and they touch each other at only one point, it means that two hemisphere meet to make one full sphere.

Therefore, the diameter of a full sphere = side length of cube.

Thus, diameter of each hemispheral holes = the diameter of a full sphere = side length of cube = 2 units.

Learn more about hemisphere on:

brainly.com/question/9280450

5 0
2 years ago
Consider this algebraic expression:     –3x + x + 5 Use the algebra tiles to model the expression.
luda_lava [24]

For this case, we have the following expression:

-3x + x + 5

We simplify the expression:

If we add similar terms, taking into account that different signs are subtracted and the sign of the greater one is placed, we have that -3x + x = -2x

So, we have to:

-3x + x + 5 = -2x + 5

Answer:

-3x + x + 5 = -2x + 5

6 0
3 years ago
Read 2 more answers
87 is what percent of 66
kozerog [31]
131.818182% and can round to 131.82
8 0
2 years ago
How to solve these 3 problems
Bingel [31]

Answer:

  1. a. decay; b. growth; c. decay; d. neither
  2. r = 4; a = 1; y = 1·4^x
  3. a. an = 3(5^(n-1)); b. f(x) = (3/5)(5^x); c. exponential growth; d. y-intercept: 3/5; first term: 3.

Step-by-step explanation:

There are two kinds of exponential problems here.

  1. exponential functions of the form f(x) = a·b^x
  2. exponential sequences of the explicit form an = a1·r^(n-1)

The second problem gives you a table that suggests the sequence form, but it asks for the exponential function form. The third problem does something similar.

__

<h3>1.</h3>

In an exponential function of the form f(x) = a·b^x, the function grows if b>1 and decays if b<1. Using this check, we can easily answer ...

  a. 0.4 < 1 . . . decay

  b. 1.3 > 1 . . . growth

  c. 1/2 < 1 . . . decay

  d. 1 = 1 . . . neither growth nor decay; the function is constant: j(x) = 1.

__

<h3>2.</h3>

The value of x is given starting at 1, so we can consider this a geometric sequence. The common ratio is r = 16/4 = 4. The first term is a1 = 4, so the explicit formula for the sequence is ...

  an = 4·4^(n-1)

When this is expanded to get rid of the constant in the exponent, we have ...

  an = 4·(4^n)·(4^-1) = 1·4^n

We recognize this form as matching the functional form f(x) = a·r^x. The multiplier of the exponential factor is a=1. In summary, ...

  r = 4; a = 1; f(x) = 1·4^x

__

<h3>3.</h3>

The first term of this geometric sequence is a1 = 3. The common ratio is r = 15/3 = 5. Using the explicit formula, we have ...

 a. explicit form: an = 3·5^(n-1)

Using the method of question 2 to write the functional form, we find ...

  an = 3(5^n)(5^-1) = (3/5)(5^n)

  b. functional form: f(x) = (3/5)(5^x)

  c. function family: exponential growth functions

 d. y-intercept: (3/5) . . . . read this from the f(x) form

     1st term: the first term listed in the given sequence is 3

_____

<em>Additional comment</em>

The "y-intercept" of a sequence is irrelevant (undefined), as the sequence term numbering starts with 1, not 0. The domain of the explicit formula is <em>natural numbers</em>, which does not include 0.

Similarly, the "first term" of a function f(x) needs further definition. Here, we've answered the question by saying the first term is f(1). There is no conventional definition of a "first term" for a continuous function.

3 0
2 years ago
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