Porobability distribution of X
x P(x)
0 0.2
1 0.4
2 0.4
Total .1.0
i] Expectation
Mean=Σxp
Variance=x²p-(∑xp)²
thus:
Mean=(0*0.2)+(1*0.4)+(2*0.4)
=0+0.4+0.8
=1.2
ii] Variance
Variance=[(0²*0.2)+(1²*0.4)+(2²*0.4)]-(1.2)²
=[0+0.4+1.6]-1.44
=0.56
hence:
standard deviation=sqrt(0.56)=0.74833
If you would like to solve for x, you can do this using the following steps:
7x + 15 = 38
7x = 38 - 15
7x = 23
x = 23/7
The correct result would be 23/7.
Answer:
the domain is -11,10 but i didnt know if you wanted that or not
Step-by-step explanation:
Answer:
The largest it can be is 39.75
Step-by-step explanation:
88.75-(24.5*2)=39.75
88 3/4 - 24 1/2 - 24 1/2 = 39 3/4
