The equation that represents a line that passed through (2,-1:2) and has a slope of 3 is y = 3x - 18
<h3>How to determine the equation of the line?</h3>
The points are given as:
(x1, y1) = (2, -12)
The slope is given as:
m = 3
The equation of the line is calculated using:
y = m(x - x1) + y1
So, we have:
y = 3(x - 2) - 12
Open the bracket
y = 3x - 6 - 12
Evaluate
y = 3x - 18
Hence, the equation of the line is y = 3x - 18
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Answer:
= 4
Step-by-step explanation:
There ar
Answer:
6
Step-by-step explanation:
Given,
...(i)
Differentiating w.r. to x.
From equation (1)
Now, at the point (1,3)
F(x) - g(x)
becomes
(3x + 2) - (x - 3)
which is
3x + 2 - x + 3
then add like terms
2x + 5
so f(x) - g(x) = 2x + 5
and it's domain should be all real numbers
