Answer:
Step-by-step explanation:
the transverse axis is horizontal.
so its a horizontal hyperbola
Center is the origin so center is (0,0)
Equation of horizontal hyperbola is
Given a= 55000 and c= 81000
c^2 = a^2 + b^2
81000^2 = 55000^2 + b^2
subtract 55000^2 on both sides
b = sqrt(81000^2 - 55000^2)= 59464.27
now plug in the values
= 2x^2 - 20x + 49 = 2(x^2 - 10x + 49/2)
y= 2((x-5)^2 - 25 + 49/2) = 2((x-5)^2 - 1/2) = 2(x-5)^2 - 1
q =5, r=-1, p=2
Vertex = (q,r) = (5,-1)
hope it helps plz mark as brainliest
If you're using a few larger intervals, then your histogram looks more stocky. If you imagine drawing one, it's because you're adding more values into the same category which can make the difference between two intervals much more noticeable. If you're using smaller intervals, however, you can much more accurately assess the difference between two different intervals. For that reason, the transition between one and another interval would look much more 'fluid'.
Answer:
-25
Step-by-step explanation:
You begin with -40, then decrease by 20 so your new value is -60, then increase by 35 so your final value is -25m... hope this helps (:
