The present age of father is 86 years old and present age of son is 48 years old
<em><u>Solution:</u></em>
Given that, a father is now 38 years older than his son
Ten years ago he was twice as old as his son
Let "x" be the age of son now
Therefore, from given,
Father age now = 38 + age of son now
Father age now = 38 + x
<em><u>Ten years ago he was twice as old as his son</u></em>
Age of son ten years ago = age of son now - 10
Age of son ten years ago = x - 10
Age of father ten years ago = 38 + x - 10
Then we get,
Age of father ten years ago = twice the age of son ten years ago
38 + x - 10 = 2(x - 10)
28 + x = 2x - 20
2x - x = 28 + 20
x = 48
Thus son age now is 48 years old
Father age now = x + 38 = 48 + 38 = 86
Thus present age of father is 86 years old and present age of son is 48 years old
I have no idea, do you mean y=mx+n cause if so it's already in that form instead that fact that the 7 is supposed to be a y
Answer:
This ordered pair is NOT a solution of the equation.
Step-by-step explanation:
First, it is important to note that ordered pairs consist of (x, y) so in this case
x = 15 and y = -3. And that any variable directly next to a number calls for multiplication. So, plugging in the variables the equation would look like
"-3 = 5 x 15"
To see if 5 x 15 = -3 we will multiply them. 5 x 15 actually equals 75 not -3. So we know this ordered pair is NOT the solution for the problem.