What you want to do for each of those is follow the formula, y-y[1]=m(x-x[1]). When I say y[1] and x[1], I mean the x and y values given. So the first one would be y-4=-3(x-(-1)). Then you solve for y by distributing the -3 to x and +1 (+1 because two negatives make a positive), making the equation
y-4=-3x-3. Then you subtract the 4. Answer #1. y=-3x-7.
#2.
y-1=1(x-4)
y-1=x-4
y=x-5
#3.
y-2=2(x-(-1))
y-2=2x+2
y=2x+4
Hope this helped you!
Answer:
A. 0.5
B. 0.32
C. 0.75
Step-by-step explanation:
There are
- 28 students in the Spanish class,
- 26 in the French class,
- 16 in the German class,
- 12 students that are in both Spanish and French,
- 4 that are in both Spanish and German,
- 6 that are in both French and German,
- 2 students taking all 3 classes.
So,
- 2 students taking all 3 classes,
- 6 - 2 = 4 students are in French and German, bu are not in Spanish,
- 4 - 2 = 2 students are in Spanish and German, but are not in French,
- 12 - 2 = 10 students are in Spanish and French but are not in German,
- 16 - 2 - 4 - 2 = 8 students are only in German,
- 26 - 2 - 4 - 10 = 10 students are only in French,
- 28 - 2 - 2 - 10 = 14 students are only in Spanish.
In total, there are
2 + 4 + 2 + 10 + 8 + 10 +14 = 50 students.
The classes are open to any of the 100 students in the school, so
100 - 50 = 50 students are not in any of the languages classes.
A. If a student is chosen randomly, the probability that he or she is not in any of the language classes is
B. If a student is chosen randomly, the probability that he or she is taking exactly one language class is
C. If 2 students are chosen randomly, the probability that both are not taking any language classes is
So, the probability that at least 1 is taking a language class is
hold on i will send in the comments i’m working on it rn
Answer:x=31.4919
Step-by-step explanation:
Step1:isolate a square root on the left hand side√x+3=√2x-1-2
Step2:eliminate the radicals on the left hand side
Raise both sides to the second power
√x+3)^2=(√2x-1-2)^2
After squaring
x+3=2x-1+4-4-4√2x-1
Step3:get the remaining radicals by itself
x+3=2x-1+4-4√2x-1
Isolate radical on the left hand side
4√2x-1=-x-3+2x-1+4
4√2x-1=x
Step4:eliminate the radicals on the left hand side
Raise both side to the second power
(4√2x-1)^2=x^2
After squaring
32x-16=x^2
Step 5:solve the quadratic equation
x^2-32x-16
This equation has two real roots
x1=32+√960/2=31.4919
x2=32-√960/2=0.5081
Step6:check that the first solution is correct
Put in 31.4919 for x
√31.4919+3=√2•31.4919-1-2
√34.492=5.873
x=31.4919
Step7:check that the second solution is correct
√x+3=√2x-1-2
Put in 0.5081 for x
√0.5081+3=√2•0.5081-1-2
√3.508=-1.873
1.873#-1.873
One solution was found
x=31.4919
Answer:
prime numbers only have two factors...
7 is the only prime in the list
Step-by-step explanation:
